You don't mention whether the 4 feet is the circumference, diameter or radius.
The area of a circle is pi times the radius squared.
If 4 feet is the circumference, the area is about 1.3 feet squared.
If 4 feet is the diameter, the area is about 12.6 feet squared.
If 4 feet is the radius, the area is about 50.3 feet squared.
Basically this isn't possible. Whenever you have an irregular curve, you need some kind of integration technique to get the area, or an estimate of the area. This can be quite simple, at least in principle: just approximate the area by narrow rectangles, calculate the area of each rectangle, and add everything up.
Pi is defined as the ratio of the circumference of a circle to its diameter (pi = circumference / diameter). So that explains why it's in the circumference formula. For the area, a little knowledge of calculus is helpful. Here's a 'simple' explanation.Suppose you have a polygon with many sides, which is inscribed into a circle. The area of the polygon can be found by adding up the areas of isosceles triangles formed by a polygon side and line segments extending to the center. If you have enough sides, then the base of each small triangle will approximately be equal to the corresponding arc of the circle. For sufficiently small triangles (a very large number of sides for the polygon), a 'long leg' of the isosceles triangle will be approximately equal to its altitude.Say that we have a 100 sided polygon, with radius R and diameter = 2*R. So lets find the approximate area of the polygon. Each base (polygon side) will be approximately equal to Circumference/100, and each altitude will be approximately equal to R. So the area of one triangle is equal to Base*Altitude/2, which is approximately (Circumference/100)*R/2. Substitute Circumference = pi*Diameter = pi*2*R.Each triangle area is approx (pi*2*R/100)*R/2 = (pi/100)*R2. Since there are 100 triangles, the polygon area is approximately pi*R2 (which is the area of the circle). Note the word approximate, because there is slight space between the polygon and the circle, but [here's the calculus part], as the number of polygon sides approaches infinity, the space between the polygon and the circle approaches zero, and the errors in approximation approach zero, so that the area of the circle and the infinite sided polygonare the same.
Triangle-least area, circle- most area, per given perimeter . The circle would have an area of 154 square cm. the triangle could have an area of almost zero if it were a long, skinny triangle. An equilateral triangle would have an area approx 92.8 sq cm.
Area of circle: 18pi Radius of circle: square root of 18 = 3 times square root of 2 Using Pythagoras' theorem each side of the square is 6 units in length
Area of circle = pi*r^2 so......... 68 sqr ft = pi * r^2 divide both sides by pi 21.645 = r^2 take square root of each side 4.7 feet = the radius of this circle
The diameter of a circle is 56 cm. What is the circumference of the circle? Use 22/7 to approximate for pi.
You don't mention whether the 4 feet is the circumference, diameter or radius. The area of a circle is pi times the radius squared. If 4 feet is the circumference, the area is about 1.3 feet squared. If 4 feet is the diameter, the area is about 12.6 feet squared. If 4 feet is the radius, the area is about 50.3 feet squared.
You don't mention whether the 4 feet is the circumference, diameter or radius. The area of a circle is pi times the radius squared. If 4 feet is the circumference, the area is about 1.3 feet squared. If 4 feet is the diameter, the area is about 12.6 feet squared. If 4 feet is the radius, the area is about 50.3 feet squared.
You don't mention whether the 4 feet is the circumference, diameter or radius. The area of a circle is pi times the radius squared. If 4 feet is the circumference, the area is about 1.3 feet squared. If 4 feet is the diameter, the area is about 12.6 feet squared. If 4 feet is the radius, the area is about 50.3 feet squared.
I'm assuming you mean the following:--------|OOO||OOO||OOO|--------Where:Each circle touches, but does not overlap, each adjacent circleThere is no gap between the edge of the circles and the edge of the squareThe area of each circle is 314 units2Let r be the radius of a circleThe area of a circle is pi x r2r = square root of (314 / pi)r = approx*. 10 unitsThe length of each side of the square = 6 x r = approx*. 60 units* approximate, because the value of pi is not exactly 3.14
You neglected to say whether the 4mm is the radius of the circle, or the diameter,or the circumference. Each possibility leads to a different area.
That depends on its radius which has not been given but the area of a circle is pi*radius squared
Each section of the circle is 1 sixth of the circle, so 1/6. 1/6 = .166666... = 16.66...%
Basically this isn't possible. Whenever you have an irregular curve, you need some kind of integration technique to get the area, or an estimate of the area. This can be quite simple, at least in principle: just approximate the area by narrow rectangles, calculate the area of each rectangle, and add everything up.
The area of a circle is the number of square units inside that circle, if each square in the circle to the left has an area of 1cm2, you could count the total number of squares to get the area of this circle. However, it is easier to use one the following formulas; A=.r²or A=pi times r times r, where A is the area and r is the radius.
Using the Circumference And Area.
You cannot get an accurate measure of the area without pi. If you are interested in an approximation, you could divide the circle up into tiny squares of some fixed area (their size would depend on how big the original circle was). Then count the number of squares where half or more is inside the circle and multiply by the area of each square. That will give you an estimate of the area of the circle. You could make an approximation with inscribed and circumscribed polygons (which are the sum of a number of isosceles triangles) and average the two areas, increasing the number of sides of the polygons to increase accuracy (that is the way the early Greek mathematicians did it). Much easier and quicker to use pi!