A parallelogram and a rhombus are both 4 sided quadrilaterals
jelly is good in my belly
This is false. Every rectangle is a parallelogram, but the converse (your statement) is not true. Imagine the set of all quadrilaterals (4 sided polygons). Within that set would be sets of kites, parallelograms, and other quadrilaterals. Within the parallelogram set, would be rectangles, rhombuses and other parallelograms. Then if a rhombus is also a rectangle, it would be a square, that would be the intersection of the set of rectangles and set of rhombuses. Hope this helps.
A parallelogram is not a statement that can be true or false.
true
False. Every rhombus is a parallelogram, but not every rhombus is a square. Only those that have right angles are squares. Every rhombus is a parallelogram because its diagonal lines are perpendicular, and they bisect an interior angle.
This is true, because a kite is a rhombus, which is a type of parallelogram.
Yes, that's a true statement.A rhombus is a special case of a parallelogram.
A rhombus is a special kind of parallelogram: one in which all sides are equal. It is not true to say that a parallelogram is never a rhombus.
A parallelogram and a rhombus are both 4 sided quadrilaterals
Yes, it is true!
False because any 4 sided polygon is a quadrilateral which includes a rhombus
False because any 4 sided polygon is a quadrilateral which includes a rhombus
jelly is good in my belly
No, it's not true. A rhombus is a special kind of parallelogram, so only some parallelograms are rhombera.
False. Not that it's never true - squares like to satisfy the conditions of all quadrilaterals at once, so you'll always find an overlap there - but a rhombus does not need to have a right angle.
This is false. Every rectangle is a parallelogram, but the converse (your statement) is not true. Imagine the set of all quadrilaterals (4 sided polygons). Within that set would be sets of kites, parallelograms, and other quadrilaterals. Within the parallelogram set, would be rectangles, rhombuses and other parallelograms. Then if a rhombus is also a rectangle, it would be a square, that would be the intersection of the set of rectangles and set of rhombuses. Hope this helps.