H= Height W= width L= Length[2(H x W)] + [2(W x L)] + [2(L x H)]
The first comprises one rectangular face and four triangular faces whereas the second has two triangular and three rectangular faces.
You find the area of the base and then find the area of one triangle. Multiply that one triangle by 4 and then add the base. The above is correct for a triangular pyramid NOT a triangilar prism. A triangular prism has two triangular ends and three rectangular faces. The rectangular faces need no be the same shape, but if they are, So Area = 2*area of triangular ends + 3*area of rectangular faces If not, you'll just have to calculate each area separately and add them.
The suface are of a rectangular prism is the area of each face added together for a total.
surface area
The total area would become 32*344 = 3096 square units.
The surface area of a rectangular prism can be calculated by adding the areas of all six faces. The formula for the surface area of a rectangular prism is 2lw + 2lh + 2wh, where l, w, and h represent the length, width, and height of the prism, respectively. This formula accounts for the two faces of each dimension (length, width, and height) on the rectangular prism.
Properties of a rectangular prism: * A rectangular prism has a total of 6 surfaces. * Because it is rectangular it will have 4 equal longer edges and 8 equal shorter edges, and so * It will have 4 rectangular faces and 2 square faces, therefore * Total surface area = 2 x square (end ) surface + 4 x rectangular (side) surfaces If we let x = shorter edges (breadth) & y = longer edges (length), and, as area = length x breadth, then * each end (a square surface) will have an area of x2 * each side (rectangular surface) will have an area of xy Thus: Total surface area of the rectangular prism = 2 x end area + 4 x side area = 2x2 + 4xy = 2x(x + 2y) Hope this nswers your question and explains how we arrive at the formula for calculating the total surface area of a rectangular prism.
To work out the area of the rectangular faces, you need to multiply the length by the width. You then need to multiply that answer by 3 (because there are 3 rectangular faces).To work out the area of the triangular faces, multiply the base of the triangle by the height and divide the answer by 2 (to find the area of one triangle). You then need to multiply it by 2 again because there are 2 triangular faces.Important: The height of a triangle is the distance from the top corner of the triangle down to the base (so that it meets the base at 90 degrees)You then need to add the total surface area of the rectangular faces to the surface area of the triangular faces to get the total surface area of the entire prism.(sorry for the essay :])
The first comprises one rectangular face and four triangular faces whereas the second has two triangular and three rectangular faces.
You find the area of the base and then find the area of one triangle. Multiply that one triangle by 4 and then add the base. The above is correct for a triangular pyramid NOT a triangilar prism. A triangular prism has two triangular ends and three rectangular faces. The rectangular faces need no be the same shape, but if they are, So Area = 2*area of triangular ends + 3*area of rectangular faces If not, you'll just have to calculate each area separately and add them.
Oh, dude, it's like super simple. So, to find the area of a rectangular prism, you just need to calculate the total surface area by adding up the areas of all the individual faces. It's like, you find the area of the base (length x width) and then multiply it by the height of the prism. Voilà, you've got the area of a rectangular prism!
L = 10W = 5H = 42 faces have area = 502 faces have area = 402 faces have area = 20Total surface area = 220 cm2
The suface are of a rectangular prism is the area of each face added together for a total.
Since the cube has 6 equal faces, the total surface area is simply 6 times the area of one of the faces. Each of these faces is a square.
A cuboid is a hexahedron. That is a solid face with six faces. More specifically, all six faces of a cuboid are rectangular. The total surface area of a cuboid with sides of length A, B and C is 2*(AB + BC + CA) sq units.
cube
PyramidV = 1/3 bhb is the area of the baseSurface Area: Add the area of the base to the sum of the areas of all of the triangular faces. The areas of the triangular faces will have different formulas for different shaped bases.