8 yds
* * * * *
That is simply nonsense.
In a regular decagon, each of the 10 sides is of the same length. So the length of each side is 22/10 = 2.2 feet.
22ft * 15ft = 330 sq ft = 30.658 sq metres
20.4 m2
22 square feet is 2.04 square meters.
264 sq ft.
1ft = 0.3048m (exactly) ⇒ 22ft x 20ft = (22 x 0.3048m) x (20 x 0.3048m) ~= 40.88m2
Perimeter = 2*(4ft 10in+6ft 4in) = 22ft 4in
The length is any number, L such that sqrt(30) ≤ L < 6 while the width, W, is 30/L so that 5 < W ≤ sqrt(30).
A speed boat is generally between 14ft and 22ft in length.
It is called a cricket pitch not a rectangle. I am unsure from memory of length but its about 22ft long from stump to stump.
22ft * 15ft = 330 sq ft = 30.658 sq metres
22ft in average
22.
approximately 6.7056 meters
22ft
Let x be the width of the rectangle. The length will therefore be x + 10 and the volume will be x(x + 10) = x2 + 10x The questuion gives the numeric value for the area as 264, so x2 + 10x = 264 => x2 + 10x - 264 = 0 => (x + 22)(x - 12) = 0 => x = -22 or x = 12. Since only a positive number can be used as a real length, the width of the rectangle is 12ft and the length is 12 + 10 = 22ft. So the dimensions of the rectangle are 22ft x 12ft.
20.4 m2
5yds=15ft+7ft=22ft