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Can you find the sum of the measures of the interior angles of a convex 70-gon?
Yes
Find the sum of the measures of the interior angles of a convex 18-gon?
Use the formula (n - 2)180 to find the sum of the measures of the interior angles of any regular convex polygon, where n is the number of sides. (n - 2)180 = (18 - 2)180 = (16)180 = 2880
Find the sum of the interior angle measures of a convex 14 -gon (a fourteen-sided polygon).?
The interior angles of a 14 sided polygon add up to 2160 degrees
Find the sum of the measures of the interior angles of a convex 22-gon?
(22-2)*180 degrees = 20*180 deg = 3600 deg.
When a convex polygon has 12 sides what is the sum of the measures of the interior angles?
To find the sum of the interior angles of a convex 12-sided polygon, you use the formula (n-2)180 n being the number of sides Therefore, (12-2)180 = 10(180) = 1800 degrees So the sum is 1800 degrees I believe this is right, but please correct me if I am wrong.
Can you find the sum of the measures of the interior angles of a convex 70-gon?
Yes
Find the sum of the measures of the interior angles of a convex 30-gon?
5040
How do you find the sum of the interior angels of the indicated convex polygon?
The sum of the interior angles of an n-gon is (n-2)*180.
Find the sum of the measures of the interior angles of a convex 18-gon?
Use the formula (n - 2)180 to find the sum of the measures of the interior angles of any regular convex polygon, where n is the number of sides. (n - 2)180 = (18 - 2)180 = (16)180 = 2880
How do you find the sum of all the angle in a convex polygon?
If the polygon (convex or concave) has n sides, then the sum of its interior angles is 180*(n-2) degrees. The sum of its exterior angles is 360 degrees - irrespective of the number of sides.
Find the sum of the interior angle measures of a convex 14 -gon (a fourteen-sided polygon).?
The interior angles of a 14 sided polygon add up to 2160 degrees
Find the sum of the measures of the angles in a convex heptagon?
The sum of the angles is 900 degrees - and the polygon does not need to be convex.
Find the sum of the measures of the interior angles of a convex 22-gon?
(22-2)*180 degrees = 20*180 deg = 3600 deg.
How do you find the sum of the measures of the angles of a quadrilateral?
I'm not sure if you mean interior or exterior angles, so I'll give you an answer for both.For interior angles:The sum of the measures of the *interior* angles of a quadrilateral is always 360 degrees. To understand why this is true, recall that the sum of the interior angles of a triangle is 180 degrees. Now, in any quadrilateral, we can draw a diagonal, splitting it into two triangles.So, the sum of the interior angles of the quadrilateral will be the sum of all of the interior angles of the two triangles, in other words, 2x180.In general, an n-gon can be divided into n-2 triangles, so the sum of the interior angles of an n-gon is 180x(n - 2) = 180xn - 360For exterior angles:The sum of the exterior angles of any closed, convex figure will be 360 degrees. So, if the quadrilateral is convex (isn't bent inwards) the sum of the exterior angles will be 360 as well.
Find the sum of the measures of the interior angles of a 13gon?
find the sum of the measures of the interior angles of 13-gon.
When a convex polygon has 12 sides what is the sum of the measures of the interior angles?
To find the sum of the interior angles of a convex 12-sided polygon, you use the formula (n-2)180 n being the number of sides Therefore, (12-2)180 = 10(180) = 1800 degrees So the sum is 1800 degrees I believe this is right, but please correct me if I am wrong.
Find the sum of the measures of the angles of a convex of a 50-gon?
9000
