pi * radius2 * height
volume of a regular right circular cylinder is V=pi(r2)h since the radius is (a) then the height of the circular cylinder would be (2a) so the volume of the largest possible right circular cylinder is... V=2(pi)(r2)(a) with (pi) being 3.14159 with (r) being the radius of the circle on the top and bottom of the cylinder with (a) being the radius of the sphere
Area of a circle = (pi)r2 [Areacircle = pi time the radius squared.] Volume of a cylinder = (pi)r2h [Volumecylinder = pi times the radius squared times the height.] (This applies to a right circular cylinder. :)
The volume is 47.12 cubic meters.
A cylinder with a radius of 3 meters and a height of 5 meters has a volume of 141.37 cubic meters.
V=hπr2
pi * radius2 * height
Pi x r² x h
Pi * r-squared * hAnswerAnd if your cylinder is not a right circular one, things get a bit tricky from there. =)
The volume of a right circular cylinder with a diameter of 6.8 in and a height of 2 feet is: 871.6 cubic inches.
Volume = Area * Length The volume of a right circular cylinder is πr2h where r is the radius of the base and h is its height (altitude)
volume of a right circular cylinder is v = (pi)(h)(r^2) if you want the answer in cubic meters the height and the radius must be in meters.
volume of a regular right circular cylinder is V=pi(r2)h since the radius is (a) then the height of the circular cylinder would be (2a) so the volume of the largest possible right circular cylinder is... V=2(pi)(r2)(a) with (pi) being 3.14159 with (r) being the radius of the circle on the top and bottom of the cylinder with (a) being the radius of the sphere
volume of a cylinder = pi*radius2*height rearrange the formula to make the height the subject of the formula: height = volume/(pi*radius2) height = 48/(pi*22) = 3.819718634 centimeters
Archimedes
Volume of the cylinder: pi*radius*radius*height
Pi x r2 x h