......A..B...C...D.. E...1...2...3...4... F...5...6...7...8... G...9..10..11.12. H..13..14.15.16. There are ten rows - A, B, C and D, going downwards - E, F, G and H going across, and 1,6,11 and 16 & 4, 7, 10 and 13 going diagonally.
10
10 triangles....
Pick a point around the center of the polygon. Join each vertex to this point. You will now have 10 triangles. The total angle of these 10 triangles is 10x180 degrees. Now you need to subtract the angles of the ten triangles at the center (which is 360 degrees). Therefore total internal angles is (10x180)-360 = 1800-360 which is 1440 degrees. A 10 sided polygon has 20 internal angles. So each angle would be 1440/20 = 144/2 = 72 degrees
There are 8 triangles inside a 10 sided decagon
Pick a point around the center of the polygon. Join each vertex to this point. You will now have 10 triangles. The total angle of these 10 triangles is 10x180 degrees. Now you need to subtract the angles of the ten triangles at the center (which is 360 degrees). Therefore total internal angles is (10x180)-360 = 1800-360 which is 1440 degrees.
by 2 rows
Two ways only. 4 rows with 25 stamps each or 5 rows with 20 stamps each.
in the form of a start
Yes it is possible!O.........O.........O.....O....O....OO.........O.........OFind the 10 Rows - trust me they are there!(The dots are only there as place markers)
Draw a regular five-pointed star. Place a coin at each of the points and each of the intersections.
The key is for the different apples to participate in more than one row each. This can be done when putting them in the shape of a 5-pointed star.
5 rows with 14 in each row7 rows with 10 in each row
The answer is to arrange them into a five pointed star. See http://www.puzzles.com/PuzzlePlayground/10in5Rows/10in5RowsSol.htm for an illustration of the solution.
1 row of 100 chairs. 2 rows of 50 chairs. 4 rows of 25 chairs. 5 rows of 20 chairs. 10 rows of 10 chairs. 20 rows of 5 chairs. 25 rows of 4 chairs. 50 rows of 2 chairs. 100 rows of 1 chair. Or you could put them all in one big circle.
if there are ten rows with three buttons each, then there are 30 buttons!
impossible simply try drawing it. does it work
Six ways. 15 rows of 2 trees 6 rows of 5 trees 3 rows of 10 trees and 2 rows of 15 trees 5 rows of 6 trees 10 rows of 3 trees * * * * * How about 1 row of 30 trees and 30 rows of 1 tree each?