If side is given too, then you can find area with one diagonal.
As diagonals bisect each other in a rhombus at 90°, Using Pythogoras Theorem:
(Half d1)² = (side)² - (Half d2)²
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There is no specific "formula." If you want the area of a rhombus, that is just A = bh/2 or (1/2)xy where x and y are the lengths of the diagonals.
Parallelograms of any form, a square, a rectangle, and a rhombus are just special parallelograms so all will form 2 pairs of isosceles triangles when a diagonal is drawn.
DO this: Take 450=1/2(25+x) then you will get your answer i am in h. geo too!1 So its easy to me .. just remember that!
It's both. A rhombus is just a parallelogram where the sides have equal length.
Ah, let's paint a happy little picture here! To find the diagonal of a rectangle, we can use the Pythagorean theorem. So for a 30x40 building, we can calculate the diagonal using the formula: √(30^2 + 40^2) = √(900 + 1600) = √2500 = 50 feet. Just like that, we've added a lovely diagonal to our building!