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What is the formula to calculate the cg line of angles?
100×100angle CG line formula
What does CG mean for diamonds?
CG is a term apparently associated with industrial diamonds, purposes for which about 75% of all mined diamonds are used.
What does 15 pts and CG 375T mean if stamped inside a diamond ring?
Is it a gold ring? If it is the 15 pts means it is 9 carat gold. Not sure about thr other stamp though.
A line connecting a vertex of a scalene triangle with the midpoint of the opposite side is a ...?
A segment that joins a vertex of a triangle and the midpoint of the side opposite that vertex is called a median. The three medians are concurrent at the centroid (the point of their intersection, and it is two-thirds of the way down each median. For example, if the three medians AA', BB', and CC' of the triangle ABC, intersect at G, then AG = 2GA', BG = 2BG', and CG = 2CG')
What is the proof of the area of a triangle equals the exradius TIMES the semiperimeter minus the side in question?
The area of a triangle is the in-radius times the semi-perimeter. [This well-known result can be seen as follows: Connect the incenter to each vertex, thereby dividing the original triangle into three sub-triangles. Their areas are each half of base (a side) times height (the in-radius).] Now, select a vertex, say A, and draw the ray through the incenter -- call it I. This ray also passes through the ex-center opposite A -- call it D. Drop perpendiculars from I and D to side AB (extended) -- call their feet E and F, respectively. Two similar right triangles are generated: AIE and ADF. Sides are proportional, so DF/IE = AF/AE. The left ratio is the ex-radius (opposite A) to the in-radius. The right ratio is the semi-perimeter to the semi-perimeter minus side BC (opposite A). Therefore ex-radius times (semi-perimeter minus BC) = in-radius times semi-perimeter, which is the triangle's area as shown above. To see that AF is the semi-perimeter: Drop perpendiculars from D and I to AC (extended) -- call their feet G and H respectively. Let the excircle opposite A (which is centered at D) be tangent to BC at T. The two tangent segments from A to the excircle opposite it are equal: AG = AF. But likewise the two tangent segments from C are equal: CG = CT, and the two from B are equal: BF = BT. So the bent line ACT = ACG = ABF = bent line ABT, and since ACT and ABT between them cover the triangle's perimeter, all four are the semi-perimeter. To see that AE is the semi-perimeter minus side opposite A: Drop a perpendicular from I to BC at J. Then the triangle's perimeter is divided into six pieces: BJ = BE (tangent segments), AE = AH (tangent segments), and CJ = CH (tangent segments). The semi-perimeter is the sum of one from each pair, e.g., AH + BJ + CJ. But BJ + CJ is the side opposite A, so AH alone is the semi-perimeter minus the side opposite A. Rick Luttmann, Sonoma State University
