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Divide the base of the triangle into five equal lengths.
Draw lines from the opposite vertex to each of these dividing points. The triangle will be divided into five parts, each with the same area.
The base is 1/5 of the original base, and they all have the same height - the same as in the original triangle.
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How many ways can you divide a triangle in equal parts?
three
Can a triangle be divided into three equal parts?
no there is no way to correctly divide a triangle into three equal parts. One side will always turn out an inch or so larger.
A 30 o-60 o-right triangle is half of what other kind of triangle?
90
Divide a triangle into 3 equal parts?
You can't. edit: If it is an equilateral triangle, draw a line from each corner towards the centre of the opposite side, but stop where the lines cross.
How do you find the area of an isosceles triangle with 2 equal sides and 1 angle?
It really depends on the angle. If the angle is at the point where the two equal sides intersect then you can divide the triangle into two equal parts (forming a right angle with the base), divide the angle by two, then use the following equation(side*arccos(your angle/2))*((side*arcsin(your angle/2)))if the angle is not where the two equal sides intersect then you can divide the triangle into two equal parts (from the point where the two equal sides intersect down to a right angle with the base) then use the following equation.(side*arcsin(your angle)*(side*arccos(your angle))
