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pi times the radius squared

pi r squared

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Q: How do you find out the area of a circle?
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Related questions

How do you find the area of a circle inside a square?

all you do is find the area of the circle... if you mean find the squares area, find the area of the circle, and then the square's area and subtract the squares area to the circles area


How find the area of a square when a circle is inside?

You find the area of the whole square first. Then you find the area of the circle inside of it And then subtract the area of the circle from the area of the square and then you get the shaded area of the square


How do you find the area of a shaded circle and the area of an unshaded circle on that is inside the other circle?

To find the area of the circle pi*radius*squared and subtract the area of the figure inside


How do you find the area of a circle if the circle is 8cm?

Area of a circle = pi*radius2


How do you find the area of only .25 a circle?

Find the area of the circle and divide by 4.


How do you find area of a circle with another circle in it?

First find the area of the larger circle and then subtract the area of the smaller circle. Area=(pi x radiuslarger)-( pi x radiussmaller)


Formula to find the area of circle?

Area of a circle = pi*radius2


How do you directly find the area of a circle?

area of a circle = pi*r2


How do you find the area of 16 wide and 27 long that has a semi circle?

how do you find the area of a semi circle


When you know the radius of a circle how can you find the area?

Area of a circle = pi*radius2


How do you find the area of a square with a semi-circle?

You add the area of the square with the area of the semi circle.


How do you find the diamter of a circle if you know the area?

In order to find the diameter of a circle if you have the area is to rearrange the formula for the area of a circle to put diameter as the unknown, like so: PIE*d = Area of a Circle d = (Area of a Circle) / PIE Therefore if the area of your circle is 40cm, 40/PIE = 12.73cm and that's the diameter.