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pythagoreon thereom 34sq - 30sq = 256 sqrt = 16 base 16+16 = 32 half length of base = SQR(34^2 - 30^2) =SQR(1156-900) =SQR(256) =16 base length = 2x 16=32

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Q: How do you find the length of the base of an isoceles triangle when both sides are 34cm and the height is 30cm?
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Related questions

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