if the perimeter is 66in and the length is 3 all u have to do is this
3+3= 6
66-6=60
60/2=30
your width of one side of the rectangle is 30in
3
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Using Pythagoras' theorem the length of the diagonal is 15 units
Perimeter, since it measures the distance around a shape. Area measures the interior. Or, more specifically, height by width, for example, 8x10 or 11x14 (inches). The perimeter for an 8x10 would be 2 times 8 plus 2 times 10, or 36 inches, but that would be insufficient to differentate an 8x10 frame from, say, a 6x12 frame (admittedly a rare size, but still possible.) So, while the common specification of a frame by height and width could be reduced to either perimeter or area, it is never done that way, precisely because important information is lost, the actual usable size of the frame.
The width of a rectangle is the shorter measurement and length is the longer. So in the case of the picture frame, 6 inches would be the width, and 10 inches would be the length.
6 in. by 8 in., 10 in. by 5 in., 12 in. by 4 in.
94 FT2
It is 2*(9+5) = 2*14 = 28 inches.
The perimeter is 2 times the length plus 2 times the width.
17.5 inches
Length and side: 7 inches and 5 inches respectively
Using Pythagoras' theorem the length of the diagonal is 15 units
The perimeter is the total of all the sides added up, which is two lengths and two widths. We can write the equation 66 = 2w + 2ℓ where 66 is perimeter, w is width, and ℓ is length. We can also write equation ℓ = 3w because the length is three times greater than the width. We can replace ℓ with 3w in the first equation because the second equation tells us they are the same thing: 66 = 2w + 2*(3w) Now we have an equation with one variable, so we can solve for that variable (w): 66 = 2w + 2*(3w) 66 = 2w + 6w 66 = 8w Divide both sides by 8: 8.25 = w The width is 6.6. We can plug that 6.6 into the equation ℓ = 3w to find the length: ℓ = 3*8.25 ℓ = 24.75 The length is 24.75. So the width is 8.25 and the length is 24.75.
It has a full perimeter frame.
If the length of each side of a rectangular picture frame needs to be 15 in and you only have 48 in of wood, use the following inequality to solve. 2l + 2w = p, in this case 2(15) + 2w <=48, so 2w <=18. The width of your fram must be 9 inches or less.
Perimeter = 100 inches Area = 600 square inches
For any perimeter, the rectangle with the greatest area is a square.For a 16-inch perimeter, the greatest rectangular area is 16 square inches,inside a square with 4-inch sides.But if you don't necessarily need straight sides, then you can squeeze more areainside the same perimeter with a circle. A circle with a 16-inch circumference has anarea of 20.372 square inches.
To calculate the area of just the frame around a photo with a 1-inch thickness, you can use a quadratic equation if the frame has a non-rectangular shape, such as a quadratic frame. If the frame is rectangular, you can use a simpler method. Assuming a rectangular frame: Let A be the area of the entire photo, and let L and W be the length and width of the photo. Let L' and W' be the length and width of the inner rectangle (the photo itself), which will be L - 2 inches and W - 2 inches, respectively. The area of the frame is then A_frame = A - A_inner = L * W - (L' * W'). If you have a quadratic frame with a specific shape, you would need to provide more details about the frame's dimensions and shape to set up a quadratic equation for its area. The general approach would be to define a quadratic function that describes the frame's area and then solve for the area by finding the roots of the equation. ʰᵗᵗᵖˢ://ʷʷʷ.ᵈⁱᵍⁱˢᵗᵒʳᵉ²⁴.ᶜᵒᵐ/ʳᵉᵈⁱʳ/³⁹⁷⁴⁶⁴/ʸᵃˢʰᵛᵃⁿᵗᵛᵃˡᵃ/ Send a message
To create a bed canopy frame, you can start by gathering materials such as wood or metal rods, a drill, screws, and a canopy fabric. Measure and cut the rods to the desired length for the frame. Use the drill to attach the rods together to form a rectangular or circular shape. Secure the frame to the ceiling or bedposts using screws. Finally, drape the canopy fabric over the frame and secure it in place.