Subtract x from both sides:-
y = -x +90
Slope-intercept form
Slope-intercept form is y = mx + b5x + 9y = -36Subtract 5x from each side:9y = -5x - 36Divide everything by 9:y = -5/9x - 4
4x+5y = 7 5y = -4x+7 y = -4/5x+7/5 in slope intercept form So the slope of the perpendicular line is plus 5/4
2x plus y = -3 (subtract 2x from both sides) y = -2x - 3 slope = -2 y-intercept = -3
Slope intercept form looks like y=mx+b, so we want to get y on on side by itself. -4x+2y=2 Add 4x to both sides: 2y=2+4x Divide both sides by 2: y=1+2x or y=2x+1
It is: y = -0.4x+1 when in slope intercept form.
y = -1.2x-3 in slope intercept form
Slope-Intercept Form: y = -2x +1
y = 6x+8 is already in slope intercept form
It is: y = -7x+1 in slope intercept form
Solving the equation for "y" gives you the slope-intercept form.
Yes, that is the slope intercept form of the equation for a straight line.
-12
y= -4x + 10 Slope intercept form is y=mx+b
Slope-intercept form
That is slope-intercept form of a line.
y = 3x + 3 is the 'slope/intercept' form. In the general eq'n of a straight line ; y = mx + c ; The slope(m) is the coefficient of 'x' and the constant(c) is the intercept on the y-axis. So for the given eq'n , The slope is '3' and and the intercept is also '3'.