23.53
It is: 24 feet by using Pythagoras' theorem
The slope is 4 (no units), and the ladder is 16.492 feet long. (rounded)
They can but don't have to as long as they are intersecting it doesn't matter whatt type of angles they form. * * * * * NO! The fact that they are perpendicular means that they intersect at right angles. Not an acute angle, not an obtuse angle but a right angle. That is what perpendicular is.
62+82=36+64=100 and the squared route of 100 is 10
It could be called angle C, as long as that name is unambiguous.
Hypotenuse = 20/sin580 = 23.58356807 Length of ladder: rounded to 23.584 feet
Then an angle of 58 degrees will be at the bottom of the ladder. Use trigonometry and the sine ratio: sin = opp/hyp and hyp = opp/sin hyp = 20/sin(58) = 23.58356807 length of ladder = 24 feet to the nearest foot
Then an angle of 58 degrees will be at the bottom of the ladder. Use trigonometry and the sine ratio: sin = opp/hyp and hyp = opp/sin hyp = 20/sin(58) = 23.58356807 length of ladder = 24 feet to the nearest foot
15 meters, or less, depending on the angle.
A ladder leaning against a 20ft wall, with an angle of 32 degrees with respect to the wall, must be 24ft long. cos(theta) = adjacent over hypotenuse cos(32) = 20 / hypotenuse hypotenuse = 20 / cos(32) hypotenuse = 23.58
Twenty divided by the cosine of 32 gives you 23.584 ft
The ladder forms the hypotenuse (r) and the wall forms the vertical (y) of a right triangle. sin theta = y / r the angle at the bottom is (90 - 32) = 58 sin 58 = 20 / r r = 20 / sin 58 = 23.583568067241928552025478405751 feet ladder must be about (rounding) 23.6 feet long.
23.58 feetA+no its not i just tryed it so yea get your facts right before putting them on herebut i dont even know this so srry for the ppl look for it
10 sin71 = 10 x 0.9455 = 9.455 feet (just under 9' 5½")
The angle of elevation of the ladder leaning against the wall is approximately 48.59 degrees.
that depends on the hieght of the building.
he should bud the ladder so it wouldn't be able to reach