23.53
It is: 24 feet by using Pythagoras' theorem
The slope is 4 (no units), and the ladder is 16.492 feet long. (rounded)
They can but don't have to as long as they are intersecting it doesn't matter whatt type of angles they form. * * * * * NO! The fact that they are perpendicular means that they intersect at right angles. Not an acute angle, not an obtuse angle but a right angle. That is what perpendicular is.
62+82=36+64=100 and the squared route of 100 is 10
It could be called angle C, as long as that name is unambiguous.
Hypotenuse = 20/sin580 = 23.58356807 Length of ladder: rounded to 23.584 feet
Then an angle of 58 degrees will be at the bottom of the ladder. Use trigonometry and the sine ratio: sin = opp/hyp and hyp = opp/sin hyp = 20/sin(58) = 23.58356807 length of ladder = 24 feet to the nearest foot
Then an angle of 58 degrees will be at the bottom of the ladder. Use trigonometry and the sine ratio: sin = opp/hyp and hyp = opp/sin hyp = 20/sin(58) = 23.58356807 length of ladder = 24 feet to the nearest foot
15 meters, or less, depending on the angle.
A ladder leaning against a 20ft wall, with an angle of 32 degrees with respect to the wall, must be 24ft long. cos(theta) = adjacent over hypotenuse cos(32) = 20 / hypotenuse hypotenuse = 20 / cos(32) hypotenuse = 23.58
Twenty divided by the cosine of 32 gives you 23.584 ft
The ladder forms the hypotenuse (r) and the wall forms the vertical (y) of a right triangle. sin theta = y / r the angle at the bottom is (90 - 32) = 58 sin 58 = 20 / r r = 20 / sin 58 = 23.583568067241928552025478405751 feet ladder must be about (rounding) 23.6 feet long.
23.58 feetA+no its not i just tryed it so yea get your facts right before putting them on herebut i dont even know this so srry for the ppl look for it
10 sin71 = 10 x 0.9455 = 9.455 feet (just under 9' 5½")
that depends on the hieght of the building.
he should bud the ladder so it wouldn't be able to reach
Answer your self dont know