The 20 cm cube can be sliced into four(a) layers - each one 20 cm wide, 20 cm long and 5cm high.
Each of those layers can be sliced into four(b) strips 20 cm wide, 5 cm long and 5 cm high
Each of those strips can be sliced into four(c) cubes 5cm wide, 5 cm long and 5 cm high
Four(a) x four(b) x four(c) = 64
How many smaller cubes are not painted at all if a cube is painted green on all sides & cut into 64 cubes of equal size?
8
1
8
Cube root of 64 is 4 therefore cube is 4 x 4 x 4. Each side of the cube has 16 visible small cube faces, 4 of which are corners (3 green sides) and 8 more are edges (2 green sides), so there are only four small cubes with one green face on each of the six sides of the large cube. Your answer is therefore 24.
To calculate the number of squares that can be cut from the card, we need to determine how many rows and columns of 5cm squares can fit within the dimensions of the card. For a 20cm by 40cm card, we can fit 4 rows of 5cm squares along the 20cm side and 8 columns of 5cm squares along the 40cm side. Therefore, a total of 4 rows x 8 columns = 32 squares can be cut from the card.
26
Cut wire into 20cm & 80cm lengths...20cm length bends into a square with 5cm sidesarea therefore = 5 x 5 = 25sq cm80cm length bends into a square with 20cm sidesarea therefore = 20 x 20 = 40sq cm25 + 400 = 425sq cm
How many smaller cubes are not painted at all if a cube is painted green on all sides & cut into 64 cubes of equal size?
20 of them.
16 1-inch cubes
that is approximately 10 cups
5760/64 = 90 cubes
0 sides are not painted! So all the cubes have three faces painted!
8
No, you cannot.
It can be.