35
There are 35 diagonals in a 10 sided decagon
A tetra-decagon is a 14 sided polygon having 77 diagonals
There are 5 sets of 3 parallel diagonals (where one is a major diagonal and 2 of them span 2 vertices. Each set makes 3 pairs, so there are 5 * 3 = 15 pairs. There are 5 sets of 4 parallel diagonals (where 2 of them span 1 vertex, and 2 of them span 3 vertices. Each set makes 6 pairs, so there are 5 * 6 = 30 pairs. So that's 15 + 30 = 45 pairs.
A decagon has 35 diagonals. A Nonagon has 27 diagonals. An Octagon has 20 diagonals. A Heptagon has 14 diagonals. A Hexagon has 9 diagonals. A Pentagon has 5 Diagonals. A Square has 2 Diagonals. A triangle has 0 Diagonals.Do you get the point?0+2+3+4+7+8. Starting with the triangle.you don't need to start with the triangle because it is 0 diagonals and will not count when you add it up anyways. And don't call it a square, call it a quadrilateral.Shut up-------Imagine a hexagone-There are two vertices at the top which make a horizontal line- Opposite them there are 2 vertices on the bottom which we can draw straight lines totherefore-There would have been 6 connections per point, but we eliminated 3(n-3)---The connections occur for every vertex in the shapethereforen(n-3)--We don't want to draw the same connections twice once we get around to vertices on the opposite side of the shapethereforen/2(n-3)where n is the number of facesThis may be applied to many if not all polygons. A Decagon has 36 sides not 35...There are 35 diagonals in a 10 sided decagon
8
There are 35 diagonals in a 10 sided decagon
A tetra-decagon is a 14 sided polygon having 77 diagonals
35.
35
A decagon has 10 sides and 35 diagonals
35 diagonals
35 diagonals
54 Diagonals. * * * * * A polygon with n sides has 1/2*n*(n-3) diagonals. So a decagon would have 1/2*10*7 = 35 diagonals. How the Community answer got 54 is anybody's guess!
There are 8
A decagon has 35 diagonals
decagon
A convex decagon has 10 sides. The formula for calculating the number of diagonals in a polygon is ( \frac{n(n-3)}{2} ), where ( n ) is the number of sides. For a decagon, substituting ( n = 10 ) gives ( \frac{10(10-3)}{2} = \frac{10 \times 7}{2} = 35 ). Therefore, a convex decagon has 35 diagonals.