Infinitely many! because there are infinitely many points on the circle. So for each ponit on the circle a ponit can be determined on the circle at a given distance from that point resulting into greatly many eaqal chords.
They are congruent They are equidistant from the center of the circle.
It gives us anything,Objectes will start urivecarning electricity.(ARE YOU DESCRIPTING YOURSELF?)This will save alot of chords in a circle.
inscribed (in geometry)
They are equidistant from the center of the circle !They are equidistant from the center of the circle.
They are equidistant from the center of the circle.
They are equal in length.
They are congruent They are equidistant from the center of the circle.
All radii of a circle are equal and all chords are line segments.
Infinite when chords are parallel to the circle's diameter
If two chords intersect within a circle, the product of the two segments of one chord equals the product of the two segments of the other chord. In short, if two chords intersect in a circle, their length is equal.
An infinite amount because a circle is a collection of infinite points.
It gives us anything,Objectes will start urivecarning electricity.(ARE YOU DESCRIPTING YOURSELF?)This will save alot of chords in a circle.
The answer is 1225.
There are an infinite number of diameters to any circle...
If they're in the same circle or in circles of equal radii (radiuses), then yes.
The circle of fifths shows the relationship between musical keys, and diminished chords are often found in the progression of chords within this circle.
Nothing special. You have two line segments with equal lengths. That's all.