There are 6 white cubes and 3 green cubes. Algebraically, the equations are W = white cubes, G= green cubes W+G = 9 and W = 2G so substituting we have 2G + G = 9, and 3G = 9, so G=3 and W=6.
Faces=9 Vertices: 9 Edges=16
Sides = Faces: 9 Edges: 21.
5 faces 6 corners 9 edges
An octagonal pyramid has 8 faces. * * * * * No. An octagonal pyramid has 9 faces - one octagonal base and 8 triangular faces meeting at an apex above the base.
Total number of faces = 9*6 = 54 Number of "hidden" faces = 2*(9 - 1) = 16 So number of painted faces = 54 - 16 = 38
3 cubes x 3 rows = 9 cubes
I am assuming that your question states that the top and sides are painted red but the bottom isn't. If so, the answer is:- There are no cubes with 4 faces painted, the most that can be painted is 3 for the ones on the corners. There are 4 corners at the top of the cube that will have their top and 2 sides painted. Therefore there are 4 cubes with 3 painted. The cubes at the corners on the second and third row down will have 2 faces painted, as will the middle cubes on the top row so there are 12 of them in this puzzle. The cube in the middle of each painted face will have just one face painted so this is 5 (assuming the bottom isn't painted). The cubes in the middle of the bottom row will also have one face painted. This brings the total to 9 That is the total of cubes that have paint on them... 4+12+9 = 25 There are 27 cubes in your puzzle so only 2 have no painted faces. The cube right in the middle and the cube in the middle of the bottom layer.
There are 6 white cubes and 3 green cubes. Algebraically, the equations are W = white cubes, G= green cubes W+G = 9 and W = 2G so substituting we have 2G + G = 9, and 3G = 9, so G=3 and W=6.
8 per cube
Faces = 9 Vertices = 9 Edges = 16
-8
* 27 edges: 9 on each end face and 9 other edges between the side faces. * 11 faces: two end faces and 9 side faces. * 18 vertices: 9 on each end face.
Sides = 9 Faces = 5
5 faces, 9 edges
An octagonal based pyramid has 9 faces
5 faces, 9 edges