There is about 11 gallons in 1.5 cubic feet so you can completely fill three 3 gallon pots.
none but 3 ft in 1yd
Oh, dude, let me like, calculate this for you. So, a 3 ft x 2 ft x 2 ft tank is 12 cubic feet. And since 1 cubic foot is around 7.48 gallons, you're looking at around 89.76 gallons of water in that tank. But hey, who's counting, right?
Area = pi*r2 where r = d/2 = 3/2 or 1.5 ft So area = 7.07 sq ft
3 yards
About 2,550 gallons.
About 3,983 gallons.
In a round pool each cubic foot accounts for 5.9 US gallons on average. If you are asking how many gallons this size pool holds, 2,548 US gallons.
25000 gallons
3,489
In order to calculate the volume of the pool, the depth must be known. Then the volume must be multiplied by the number of gallons of water per cubic foot. The surface area of an 18-ft-diameter pool is 254.47 sq ft. Multiply that number by the depth (in ft) to find the volume. Then multiply the volume by 7.481 (gallons per cu ft) to find how many gallons the pool will hold. Example, 18-ft-dia pool x 3 ft deep 254.47 x 3 = 763.41 cu ft 763.41 x 7.481 = 5711 gallon capacity
A fifteen foot diameter round pool, three feet deep has a volume of 530.144 cubic feet, this converts to 3965.752 US gallons.
Assuming you mean 6 foot diameter round pool, 2 feet deep. V=pir2h=3:14159*(3)2*2=56.5 cu ft. 56,5 cu ft x 7.48 gal/cu ft = 423 gallons
This is a standard size pool for both gunite and concrete, however the depth is more than likely 10 feet. If so, the pool holds 31,000 gallons.
269.3 gallons.
Assuming, without any justification, thatthe width of the pool is 14 feet,the length of the pool is 32 feet,the bottom of the pool drops uniformly, thenits volume is approx 11162 Imperial gallons.
If the pool measures 16-ft by 16-ft and it's 3-ft deep everywhere,then its volume is16 x 16 x 3 = 768 cubic feet = 5,745.04 gallons (rounded)That's the volume of the pool. There's no way for me to knowhow much water may be in it. It could even be empty.