no
it depends how many spokes it has
0 lines
Has 6 lines of symmetry
It has 2 symmetry lines
No. RST7.5 is a maskable interrupt on the 8085, not the 8086/8088.
There are 16 data lines in 8086.
The 8086 interrupt priorities are concerned ,software interrupt have the highest priority,followed by NMI ,followed by INTR.The lowest priority signals are unmaskable interrupts.
Interrupt vector table
The BIOS function in the 8086 microprocessor is called an interrupt function. It is an interrupt function because it is not called by a function call instruction.
There are 256 different interrupt vectors in the 8086/8088. Each vector is a far CS:IP address, which is four bytes. That makes the interrupt vector table 1,024 bytes.
The 8086 interrupt table is from 0000h to 03FFh for interrupt 0 through interrupt 255. It is common practice to design systems that use only the lower-numbered interrupts and then use the upper part of the interrupt table for code or data. For more information see: http://datasheets.chipdb.org/Intel/x86/808x/datashts/8086/231455-005.pdf
Interrupt Acknowledgegenerated by the microprocessor in response to INTR. Causes the interrupt vector to be put onto the data bus
The 8086/8088 has 20 address lines. It can access 220, or 1MB, or 1,048,576 bytes of memory.
The 8086/8088 has 20 address lines. It can access 220, or 1MB, or 1,048,576 bytes of memory.
The address lines A0..A15 are multiplexed with the data lines D0..D15 on the pins AD0..AD15
In the 8086/8088, the interrupt vector table is the first 1024 bytes of memory. In the 8085, the interrupt vector table is the first 64 bytes of memory if using the RST form of interrupt, otherwise the interrupt vector is provided by the interrupting device, usually in the form of a CALL instruction. The interrupt handler is wherever the interrupt vector points to.