3 1 curved and 2 straight
1 quadrant = 1 quadrant. Or what is the question?
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if you have a shape in quadrant 1 of a coordinate plane and another shape in quadrant 2, rotate the shape in quadrant 1 to the right 90 degrees. It, when rotated, the shape in quadrant 1 is congruent to the shape in quadrant 2, then they are rotationally symmetrical.
No. The shapes used for tessellation must be finite. A quadrant is not finite.
Second quadrant (II).
No quadrant has parallel sides.
1 quadrant = 1 quadrant. Or what is the question?
It is the sum of its 4 sides which is its perimeter.
The coordinate or Cartesian plane is divided into four quadrants by the axes. The axes, themselves, do not belong to any quadrant. Assuming the normal x and y-axes, Quadrant I : x > 0, y > 0 Quadrant II : X < 0, y > 0 Quadrant III : X < 0, y < 0 Quadrant IV: X > 0, y < 0 That's it. No special sides, nothing to solve.
Irregular polygons with any number of sides, starting with a right angled triangle. A quadrant of a circle and many other shapes.
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Quadrant I : (+, +) Quadrant II : (-, +) Quadrant III : (-, -) Quadrant IV : (+, -)
A quadrant refers to one-fourth of a circle or sphere. Therefore, the concept of square miles does not directly apply to a quadrant. Square miles is a measure of area, while a quadrant is a measure of angle or position.
In order for there to be equilibrium, or balance, within quadrants, pulleys must be on opposite sides of the quadrant. If there are four pulleys in the same quadrant, there can be no equilibrium, nor can there be equilibrium if four pulleys are in adjacent quadrants.
it is POSITIVE because tangent is said to be as OPPOSITE all over ADJACENT side of the triangle. since the opposite and adjacent sides of theta in Quadrant 3 are both negative, the quotient of two negative integers is POSITIVE. in third quadrant tanƟ= -O/-A
4 quadrant
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