(5580 + 360)/180 = 33 sides
As in the question it is 5400 degrees. But a polygon whose interior angles add up to 5400 degrees will have 32 sides
hextogonImproved Answer:-A regular pentagon which has 5 sides
an angle whose vertex is the center of the polygon and whose sides pass through adjacent vertices.
14 sides in the polygon
(5580 + 360)/180 = 33 sides
As in the question it is 5400 degrees. But a polygon whose interior angles add up to 5400 degrees will have 32 sides
It is a regular octagon which has 8 sides
hextogonImproved Answer:-A regular pentagon which has 5 sides
It is a 6 sided hexagon whose interior angles add up to 720 degrees
A polygon whose interior angles are 2880 degrees has 18 sides.
an angle whose vertex is the center of the polygon and whose sides pass through adjacent vertices.
Triangles, rectangles and octagons are all examples of a polygon. A polygon is a polygon whose sides are the same length and whose interior angles are the same measure
14 sides in the polygon
The measure of an interior angle in degrees of a regular polygon of n sides is given by the formula: 180 x (n-2) / nThe measure of an exterior angle in degrees of a regular polygon of n sides is given by the formula: 360/nIf the interior angle is 11 times the exterior angle, then:180 (n-2)/n = 11 x 360/nthen: 180 n - 360 = 11 x 360, or180 n = 12 x 360that its solution gives n = 24Accordingly, the answer is that the number of sides of this polygon is 24
2800 degrees * * * * * No. The interior angles of a polygon with n sides is (n-2)*180 degrees. Here, n = 12 so the answer is 1800 degrees. A polygon whose interior angles added to 2800 degrees would have 17 5/9 sides! Since a fractional number of sides is impossible, so is such a polygon.
This is not possible for a normal regular polygon. (A regular polygon has all equal angles and all equal sides. A normal polygon has no intersecting edges.)The smallest regular polygon is an equilateral triangle (a three sided polygon), whose exterior angle measure is twice the measure of its interior angle. A four-sided polygon (a square) has equal interior and exterior angle measures of 90⁰. Starting from a five-sided polygon, the exterior angle measure is smaller than the interior angle measure.Let's assume that the given information is true. So we need to verify it.Let's say that the interior angle of the regular polygon has a measure of x degrees, and the measure of the exterior angle of that polygon is 4x degrees.Since the sum of the interior and the exterior angles of the polygon is 180 degrees (a straight line), the interior angle is 36 degrees.4x + x = 1805x = 1805x/5 = 180/5x = 36The sum of the angles of a polygon = 180⁰(n - 2), where n is the number of the sides of the polygon.The measure of one of the angles of a polygon = 180⁰(n - 2)/n. Substituting the angle measure of 36⁰ into this formula, we have:36⁰ = 180⁰(n - 2)/n (multiply by n to both sides)36⁰n = 180⁰(n - 2)36⁰n = 180⁰n - 360⁰ (add 360⁰ and subtract 36⁰n to both sides)360⁰ = 144⁰n (divide by 144⁰ to both sides)2.5 = n !!That means that a such normal polygon does not exist.