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60.0625 square feet.

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How do you convert 1000 sq ft into square meters?

A square foot is a measure of area; 1 sq ft equals the area of a rectangle that is 1 ft wide and 1 ft long. Likewise, 1 square meter equals the area of a rectangle whose sides are 1 m long. For a square with width w and length l, you get the area a by multiplying: a = w * l As 1 ft = 0.3048 m, this equates to 1 sq ft = 1 ft * 1 ft = 0.3048 m * 0.3048 m = 0.09290304 sq m So 1 square foot = approximately .093 square meters, so 1000 square feet would equal approximately 93 square meters.


Which is the rectangular number 93 120 301?

301 * * * * * Actually, all three are.


What is the Diameter of a circle with an area of 6793?

The diameter is 93.


What is the diameter of a circle if the circumference is 93?

The diameter is 29.6


How many different isosceles triangles are possible if the sides must have whole number lengths and the perimeter must be 93 inches?

In any triangle whose sides have measures a,b, and c, the triangular inequality tells us: a + b > c a + c > b b + c > a Since the triangles here have two sides with the same measure, we will suppose that a = b and the above becomes a + a > c a + c > a a + c > a or 2a > c c > 0 c > 0 So we have 1) 2a > c > 0 Since the perimeter is 93, we have a + a + c = 93 2) 2a + c = 93 Solve 2) for c, c = 93 - 2a Substitute in 1) 1) 2a > 93 - 2a 4a > 93 a > 23.25 and since a is an integer a > 23 Solve 2) for 2a 2a = 93 - c Substitute 93 - c for 2a in 1) 93 - c > c 93 > 2c 46.5 > c and since c is an integer, 47 > c or c < 47 So we have a > 23 c < 47 Let p be the positive integer amount that a is greater than 23 Let q be the positive integer amount that a is less than 47 So a = 23 + p and c = 47 - q Substituting those into 2) 2a + c = 93 2(23 + p) + (47 - q) = 93 46 + 2p + 47 - q = 93 93 + 2p - q = 93 2p - q = 0 2p = q So now we have a = 23+p and c = 47-2p Since c > 0 47 - 2p > 0 -2p > -47 p < 23.5 and since p is an integer p < 24 And p > 0 so 0 < p < 24 So there are 23 values p can take on, any of the integers which are greater than 0 and less than 24. That's 1 through 23, so there are 23 possible isoceles triangles with integer sides that have perimeter 93. Here they all are: p a = 23+p b = a c = 47-2p ---------------------------------- 1. 24 24 45 2. 25 25 43 3. 26 26 41 4. 27 27 39 5. 28 28 37 6. 29 29 35 7. 30 30 33 8. 31 31 31 9. 32 32 29 10. 33 33 27 11. 34 34 25 12. 35 35 23 13. 36 36 21 14. 37 37 19 15. 38 38 17 16. 39 39 15 17. 40 40 13 18. 41 41 11 19. 42 42 9 20. 43 43 7 21. 44 44 5 22. 45 45 3 23. 46 46 1 Edwin

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