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A 25-foot radius circle is 1,963.5 ft2

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11y ago

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Related Questions

How many square feet in a 25 foot Radius?

1963.5 square feet.


How many square feet in a circle with a 12 foot radius?

452 square feet.


How many square feet are in a 40 foot radius circle?

That would be 5026.55 square feet.


How many square feet are in a sixteen foot radius?

To find the area of a circle with a sixteen-foot radius, use the formula A = πr², where r is the radius. Plugging in the radius, A = π(16)² = π(256) ≈ 804.25 square feet. Therefore, a circle with a sixteen-foot radius has an area of approximately 804.25 square feet.


How many square feet in a 34 foot Circle?

Area of the circle in square feet: pi*radius squared


How many square feet in a circle with a 6 foot radius?

28.27 ft2


How many square feet in a 75 foot radius?

233.5 sq ft


How many square feet in a five foot radius circle?

78.54 ft2


How many square feet in a 91 linear foot radius?

A circular shape, with a radius of 91 feet ahs an area of pi*912 = 26,016 sq feet, approx.


How many square feet in a 2 foot circle?

Area = pi*r2where r is the radius of the circle.A 2-foot circle has a radius of 1 ft so area = pi square feet ie 3.14 sq feet, approx.Area = pi*r2where r is the radius of the circle.A 2-foot circle has a radius of 1 ft so area = pi square feet ie 3.14 sq feet, approx.Area = pi*r2where r is the radius of the circle.A 2-foot circle has a radius of 1 ft so area = pi square feet ie 3.14 sq feet, approx.Area = pi*r2where r is the radius of the circle.A 2-foot circle has a radius of 1 ft so area = pi square feet ie 3.14 sq feet, approx.


How many square feet in a 54 foot circle?

To find the area of a circle, you can use the formula A = πr², where r is the radius. For a 54-foot circle, the radius is 27 feet (half of the diameter). Therefore, the area is A = π(27)², which is approximately 2,295.6 square feet.


How many square feet in a 54 foot circle by 5 feet wide?

The answer depends on what the 54 feet measures: the radius, diameter or circumference.