None, since there can be no conversion.
A gallon is a measure of volume in 3-dimensional space while a square foot is a measure of area in 2-dimensional space. The two measure different characteristics and, according to the most basic principles of dimensional analysis, any attempt at comparisons or conversions between the two are fundamentally flawed.
The dimensions of an average 55 gal drum are 24in in diameter and 36in in height.
So, you simply take the formula for the circumference of a circle, which is
Cir = 2πr, where π=3.14 and r is the radius or half the diameter
AND multiply this number by the height.
This will give you the overall square inches of the surface of the drum.
THEN, divide this number by 144 sq in/sq ft. This will give you the square footage of the surface.
Here we have:
(2 x 3.14 x 12in) = 75.36in
75.36in x 35 in = 2637.6 sq in.
2637.6 sq in ÷ 144 sq in/sq ft = 18.32 sq ft.
213,000 gal / 7.48 gal /cubic foot =28,476cf /12ft(depth)=2373 sqft of surface area
1870.13 gallons per inch of depth. 144 sq. ins./sq. ft. X 3000 sq. ft.= 432,000 sq. ins. 1 gal. = 231 cu. ins. = 231 sq. ins X 1 in. deep. 432,000 sq. ins. / 231 sq. ins. per gal @ 1 in. depth = 1870.12987+ gallons @ 1 in.
(250,000,000 gallons) x (231 in3/gal) x (1 foot/12inch)3 x (1 acre/43,560 ft2) =767.221 acre-feet. (rounded) What does this mean ? Right now, it looks kind of ridiculous.Well, it's not so bad. It means a foot of rain over 767 acres, or about1.44 inches of rain over 10 square miles, which isn't so unreasonable.
8"gl" does not make any sensebut there are eight pints (abbreviated pt.) in a gallon (abbreviated gal.)
A 3x2x2 ft tank has a volume of 12 cubic feet, and the only needed conversion factor is 1.00gal/.133681ft3. Knowing that, your tank has about 89.77 gallons of water. Further, considering that 89.77 US gal of water fills to tank to overflowing, an ullage must be considered to allow for expansion of the contents due to temperature changes. In design work, a practical maximum would be in the 85 US gal range.
3
62.3 Imperial gallons.
616 lbs
.2723122 to be exact
The standard industrial oil (or barrel) drum has a capacity of 200-liters. In United States gallons (gal) one barrel holds 55-gal.
Volume = 55 gallons = 12,705 cubic inches = 7.3524 cubic feet (rounded)
Height = 36 inches (3 feet) Diameter = 21 inches
There are 2,419.5 square feet in a 12,000 gallon pool if it is 6 feet deep. This can be calculated by converting gallons to cubic feet and then dividing by the depth of the pool in feet.
There are 4 qt per gallon SO ...4 qt/gal x 48 gal = 192 qt.
1 US gallon = 0.133680556 cubic feet so about 7 1/3 in a 55 gallon drum
1,800,000 gallons equates to 5.524 acre-feet.
Take the hightx the withx the depth and multiply by 12 then divide by 231 and that will give you the app. number of gallons in your case it would be 1501.29 gal. there is 231 cuibic in. per gal appx.