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If the ratio of areas of two squares is 2 to 1 then what is the ratio of their sides?
Let A1 be the area of the first square and X the length of its side Let A2 be the area of the second square and Y the length of its side A1 = X2 , A2 = Y2 , A1/A2 = X2/Y2 , Square Root (A1/A2) = Square Root ( X2/Y2), X/Y = Square Root (A1/A2) = Square Root (2/1) = 1.414
What is the length of the hypotenuse of a right triangle that has a base of 5 inches and a height of 12 inches?
In any right triangle, the hypotense squared = the square of one side + the square of the other side. h2 = a2 + b2 Here, h2 = 52 + 122 = 25 + 144 = 169 We have h2 = 169 The square root of 169 is 13, so the length of the hypotenuse is 13 inches.
The volume of a cube is 64 cubic inches Its total surface area in square inches is?
Denoting a to be the cube's side, its volume is equal to a3. Therefore, if V = 64 in3:a = 641/3 = 4 inA cube has six faces, with each of their surface area being equal to a2; hence:Total area = 6 a2 = 96 in2
How do you find side a if side b is 12 inches and side c is 18 inches of a right triangle?
The answer depends on whether a or c is the hypotenuse: b cannot be the hypotenuse since the hypotenuse MUST be the longest side. Suppose a is the hypotenuse. Then a2 = b2 + c2 = 122 + 182 = 144 + 324 = 468. So a = 21.63 inches (approx). Suppose c is the hypotenuse. Then c2 = b2 + a2 = 182 = 122 + a2. So a2 = 180 and a = 13.42 inches (approx).
What is the square root of a squared plus a squared equal?
sqrt(a2 + a2) = sqrt(2a2) = sqrt(2)*sqrt(a2) = sqrt(2)*asqrt(a2 + a2) = sqrt(2a2) = sqrt(2)*sqrt(a2) = sqrt(2)*asqrt(a2 + a2) = sqrt(2a2) = sqrt(2)*sqrt(a2) = sqrt(2)*asqrt(a2 + a2) = sqrt(2a2) = sqrt(2)*sqrt(a2) = sqrt(2)*a
