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A shape that has seven sides?
septagon septagon * * * * * Actually, it is called a heptagon.
How many sides does a septagon has?
It has 7 sides and it is also known as a heptagon
What is a 7-sided shape called?
Heptagon/Septagon it can be either
How many vertices does a icosidodecahedron have?
it has 30 vertices
How many vertices does a hendecagon have?
11 vertices
How many vertices dose a septagon have?
It has 7 vertices
How many diagonals in a septagon?
Not sure about a septagon, but there are 14 diagonals in a heptagon.
How many 35 sides a septagon/heptagon?
The answer is 35
What is another name for a septagon?
another name for a septagon is a heptagon
What is a seven sided polygon is called a?
a heptagon
A shape that has seven sides?
septagon septagon * * * * * Actually, it is called a heptagon.
How many diagonals does a septagon have?
There are 14 diagonals in a septagon. Another name for a septagon is heptagon. This is a seven-sided polygon. To figure the numbers of diagonals, you can use the formula 1/2 x [n x (n-3)], where n is the number of sides.
How many sides does a septagon has?
It has 7 sides and it is also known as a heptagon
Is a septagon a parallelogram?
No because a septagon is the same as a heptagon which is a 7 sided polygon
How many diagonals in a 50-gon?
for any polygon with 'n' number of sides, the number of diagonals will be n(n-3) / 2 if n is 50, no. of diagonals will be 50(50-3)/2 = 47*25 = 1175 how do you get it? take any polygon, say septagon i.e. with 7 sides if you take 1 vertice, remainig vertices will be 7-1 that is 6. there will be 2 consecutive vertices for any vertice, so here, this one has 2 consecutive vertices(its always like that) so the remaining vertices is 6-2 that is 4. remember : a diagonal connects non consecutive vertices so you know that from one vertice, there will be 4 diagonals. multiply it by the total no. of vertices(here 7) 4*7 = 28 now divide this by 2 (since 2 vertices share the same diagonal) therefore, 28/2 = 14 which is the no. of diagonals in a septagon. so for an n-gon, the number of diagonals will be n(n-3) / 2 hope it helps! p.s. i figured it out myself during math class. then i tried it on many polygons.
How many diagonals in 50-gon?
for any polygon with 'n' number of sides, the number of diagonals will be n(n-3) / 2 if n is 50, no. of diagonals will be 50(50-3)/2 = 47*25 = 1175 how do you get it? take any polygon, say septagon i.e. with 7 sides if you take 1 vertice, remainig vertices will be 7-1 that is 6. there will be 2 consecutive vertices for any vertice, so here, this one has 2 consecutive vertices(its always like that) so the remaining vertices is 6-2 that is 4. remember : a diagonal connects non consecutive vertices so you know that from one vertice, there will be 4 diagonals. multiply it by the total no. of vertices(here 7) 4*7 = 28 now divide this by 2 (since 2 vertices share the same diagonal) therefore, 28/2 = 14 which is the no. of diagonals in a septagon. so for an n-gon, the number of diagonals will be n(n-3) / 2 hope it helps! p.s. i figured it out myself during math class. then i tried it on many polygons.
What is a 7-sided shape called?
Heptagon/Septagon it can be either
