10,764 feet
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For a three-acre square-shaped lot, you'd need a minimum of about 1,446 feet of fencing.
It depends on what kind of animal you are trying to fence in (or out). For an average cattle pasture, I prefer setting them 10 feet apart, so you would need about 150 T-posts. I still prefer setting three six-inch treated wooden posts for each corner; they will hold up better to the tensioning of the fence/barb wire.
That depends on the shape of the lot. But, assuming the lot is a perfect square, you would need 10,560 feet (two miles) of fence to surround it.
To fence in 2 acres, you first need to determine the perimeter. Since 1 acre is 43,560 square feet, 2 acres equals 87,120 square feet. Assuming a square shape for simplicity, each side would be approximately 417 feet long, giving a perimeter of about 1,668 feet. If fence posts are placed 12 feet apart, you would need about 139 posts (1,668 feet ÷ 12 feet per post).
To determine the amount of fence needed for a perimeter fence around 8 acres, we first need to convert the area from acres to square feet. Since 1 acre is equivalent to 43,560 square feet, 8 acres would be 8 x 43,560 = 348,480 square feet. The perimeter of a rectangular area can be calculated by using the formula P = 2(l + w), where P is the perimeter, l is the length, and w is the width. If we assume the area is a square (which maximizes the perimeter for a given area), we can find the length of one side by taking the square root of the total area, which gives us approximately 590.61 feet. Therefore, the total amount of fence needed for the perimeter would be 4 x 590.61 = 2,362.44 feet.