12j
Hi, This is more of a physics question, but can be solved using the equation; Work = Force * distance Thus; W = Fs W = 6 * 2 W = 12 Nm-1 where; W = work F = Force in Newtons s = distance over which the work is done (in meters)
When a stone comes out of the ground it may have different shapes, cubes, rhombic or dodecahedral. None of those shapes have the brilliance, shape or shine that you'd associate with the rings and necklaces at your local jeweler. So, rough stones are sent to a cutter who uses various tools and polishing methods to shape and smooth the stone to get the best possible aesthetics from it. When the cutter is done it has gone from being a rough to a cut stone.
Yes they are not the most exciting but it can be done.
no
Done!
Hi, This is more of a physics question, but can be solved using the equation; Work = Force * distance Thus; W = Fs W = 6 * 2 W = 12 Nm-1 where; W = work F = Force in Newtons s = distance over which the work is done (in meters)
If a 100 N box is lifted 3 meters off the ground, the answer is 300 joules.
If a 100 N box is lifted 3 meters off the ground, the answer is 300 joules.
(4 x 5) kilogram-meters = 20 joules
If a 100 N box is lifted 3 meters off the ground, the answer is 300 joules.
A 0.650 kg basketball is dropped out of a window that is 6.46 m above the ground. The ball is caught by a person whose hands are 1.32 m above the ground. How much work is done on the ball by its weight?
100 x 3 = 300 joules
It depends on the weight. The work required in joules (kg*m2/s2) is equal to the force applied in newtons and the displacement, or distance, in meters. Thus, for an object that weights 1 N (multiply the weight of the object by the gravitational acceleration, 9.81 m/s2 to transfer to newtons) will require 1 N * 3 m = 3 J. Thus, the formula for work is: W = Fd "W" is the work done on the system. "F" is the force in newtons "d" is the displacement (or distance) of the object in meters.
Work = force x displacementW = Fd W = 100N x 3m W = 300J 300 joules of work is done on the box.
work=force(distance) work=500(20) work=10000 joules
5 feet = 1.524 meters. Done.
Work is done in lifting is equal to work done in opposing gravity. Work done in opposing gravity = weight times distance = 700 x 4 =2800 joules