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ax+by=c

2x+3y=11

3y=-2x+11

(3y=-2x+11)/3= y=-2/3x+11/3 slope intercept form

5=-2/3(6)+b replace x and y with point given

5=-4+b

9=b

therefore

y=-2/3x+9

2x+3y=27

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Q: How would you Write an equation that passes through the point 6 5 and is parallel to the line whose equation is 2x 3y equals 11?
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