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Zero.

For instance, given a right triangle with points ABC. where AC is the hypotenuse, then to find the angle between AB, we take sin(AB/AC), where AB is the distance between points A and B, and AC is the distance between A and C. If we replace AB with 0, the equation would be sin(0/AC). Sine of zero is always zero.

Q: If AB equals 0 what is the angle between a and b?

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An acute angle is an angle measuring between 0 and 90 degrees.

this is a continuation of the question... AB=4, BC=6, AE=8, and BE intersects at D

Any angle that you like. The only limitation on any single angle of an octagon is that it lies between 0 and 360 degrees..

Any angle between 0 degrees and 90 degrees is called an "acute" angle.

A line which intersects another line at an angle between 0 and 180 degrees.

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Assuming that cross means 'divide' B is equal to 0

An acute angle is greater than 0 but less than 90 degrees

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ab=1a+1b a is equal to either 0 or two, and b is equal to a

Cross product tests for parallelism and Dot product tests for perpendicularity. Cross and Dot products are used in applications involving angles between vectors. For example given two vectors A and B; The parallel product is AxB= |AB|sin(AB). If AXB=|AB|sin(AB)=0 then Angle (AB) is an even multiple of 90 degrees. This is considered a parallel condition. Cross product tests for parallelism. The perpendicular product is A.B= -|AB|cos(AB) If A.B = -|AB|cos(AB) = 0 then Angle (AB) is an odd multiple of 90 degrees. This is considered a perpendicular condition. Dot product tests for perpendicular.

0

No, but it helped.

An angle that measures between 0 and 90 degrees is an acute angle.

Is an acute angle.