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Let the shorter leg be x-5 and the other leg be x.

Use Pythagoras' theorem:

(x-5)2+x2 = 625

(x-5)(x-5)+x2 = 625

2x2-10x+25 = 625

2x2-10x+25-625 = 0

2x2-10x-600 = 0

Solving the above using the quadratic equation formula works out as:

x = -15 or x = 20, so it must be the latter because dimensions can't be negative.

Therefore:the shorter leg is 15 cm

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Q: If one leg of right triangle is 5cm shorter than the other leg The length of the hypotenuse is 25cm Find the length of the shorter leg?
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