True!
true
It’s true (apex)
True
True
I think that you are asking for the equation of a semi-circle. If you have a circle with radius r and centered at (0,0), its equation is x^2 + y^2 = r^2 The upper semicircle has the equation: y = sqrt(r^2 - x^2) with -r ≤ x ≤ r <------------------ Answer By using the square root I only get points where the y coordinate is positive and thus all points are restricted to the upper semicircle. The area is ((π * r^2) / 2) The perimeter is (π * r)
If the coordinates of the three vertices are A = (p, s) B = (q, t) and R = (r, u) then centroid, G = [(p+q+r)/3, (s+t+u)/3].
It’s true (apex)
No. If the points are all in a straight line, then they could lie along the line of intersection of both planes. Mark three points on a piece of paper, in a straight line, and then fold the paper along that line so that the paper makes two intersecting planes. The three points on on each plane, but the plants are not the same.
coplaner points- are points lying on his the same plane,.. solution: plane R contains XY XY contains X and Y...
True
True
a b c, t r w, z p t; any three variables
A cube has 8 non-coplanar points at the vertices and has 6 faces. This is only a partial answer...3 points determine a plane so there will be many more than 6. Your answer is going to be found by the formula n!/(n-r)! where n=8 and r=3. That gives: 40320/120 = 336
Yes, you can consider it a relation between the points on the x-axis, and the points on the y-axis. In fact, ANY subset of R squared (in other words, any subset of the points on a plane), including the empty set, sets that contain single points, and larger sets, can be considered a relation in R squared (i.e., two sets of real numbers).
Draw R. T and Y is a straight line with a line drawn through it. Put arrows on that line. Draw a large parallelogram around that and label it with a capital italics W.
H. R. Kingston has written: 'Metric properties of nets of plane curves ..' -- subject(s): Plane Curves
you need also an angle (theta) besides the radius. Then assuming that the starting point of both plane and Cartesian plane is the same: x=R*cos(theta), y=R*sin(theta)
An upright, inverted image of the letter R. Much like this - я