X=30
2x+2x+x+30=180; All of the angles in a triangle always add up to 180.
Therefore 5x+30=180; subtract 30 to be 5x by itself.
Therefore 5x=150; divide by 5 to find x.
Therefore X=30
2(30)+2(30)+30+30=180
The 3 interior angles of a right angle triangle add up to 180 degrees and so:- If: x+15+2x+90 = 180 Then: 3x = 75 and so x = 25 Therefore the largest acute angle is 2x = 50 degrees Check: 45+55+90 = 180 degrees
The sum of the angles in a triangle is 180. Since the ratio of the angles is 2:3:5 their measurements are 2x, 3x, and 5x. When you add them together you will get 180. So... 2x+3x+5x=180 10x+180 x=18 Since x=18 the measure of the angles are 2x=36 3x=54 5x=90 Since one of the angles is 90 we know that the triangle is a RIGHT triangle.
Assuming A, B and C are angles, it is an obtuse angled triangle.
Well if it has 180 degrees over all, and the two base angles have to be congruent, then the equation is 180-120=2x or each base angle is 30 degrees.
If you mean y = 2x+3 and y = -1/2x+4 then the two lines are perpendicular to each other meeting at right angles.
The 3 interior angles of a right angle triangle add up to 180 degrees and so:- If: x+15+2x+90 = 180 Then: 3x = 75 and so x = 25 Therefore the largest acute angle is 2x = 50 degrees Check: 45+55+90 = 180 degrees
The sum of the angles in a triangle is 180. Since the ratio of the angles is 2:3:5 their measurements are 2x, 3x, and 5x. When you add them together you will get 180. So... 2x+3x+5x=180 10x+180 x=18 Since x=18 the measure of the angles are 2x=36 3x=54 5x=90 Since one of the angles is 90 we know that the triangle is a RIGHT triangle.
The interior angles of a triangle add up to 180. So a triangle with 3 equal sides (or angles) will have 60-degree angles. * * * * * True, but the question is about an isosceles triangle, not an equilateral triangle. The angles of an isosceles triangle are x, x and 180-2x degree where x is a measure between 0 and 90 degrees.
The sum of the interior angles of a triangle is 180o. In an isosceles triangle two of the angles are the same, say x. The third angle is then 180o-2x.
Without seeing a diagram of the triangle and any possible angles: 153 > x > 372/3 There will be no triangle if the sum of the two shorter sides is less than or equal to the length of the longest side. This occurs if: 2x + (x+ 20) ≤ 133 ⇒ x ≤ 372/3 or if: 2x ≥ (x+ 20) + 133 ⇒ x ≥ 153
Assuming A, B and C are angles, it is an obtuse angled triangle.
X = 180 - Y so 180 - Y = 2x + 4 and Y = 4x + 20 so 180 - 4x - 20 = 2x + 4 therefore 6x = 156 so x = 26 making Angle X = 56o and Angle Y = 124o
middle angle= 51 degrees smallest angle= 25 degrees largest angle= 104 degrees x=25 ; y=104 I can't really show you how I got the answer but I suggest you draw a picture and then it's much easier to figure out. We don't need a figure to compute the measure of the angles, since we know that the sum of the measure of angles in a triangle is 180 degrees. Let x be the smallest angle, so the middle angle is 1 + 2x, and the larger angle is 53 + 1 + 2x or 54 + 2x. Then we have: x + (1 + 2x) + (54 + 2x) = 180 5x + 55 = 180 5x + 55 - 55 = 180 - 55 5x = 125 5x ÷ 5 = 125 ÷ 5 x = 25 1 + 2x = 1 + 2(25) = 51 54 + 2x = 54 + 2(25) = 104
I see that your given information is about the angles of the rhombus. Then, 2x + 5 + 2x + 1 = 180 combine like terms on the left side 4x + 6 = 180 subtract 6 to both sides 4x = 174 divide by 4 both sides, then simplify the result x = 87/2 degrees.
Well if it has 180 degrees over all, and the two base angles have to be congruent, then the equation is 180-120=2x or each base angle is 30 degrees.
Complementary angles equals 180 degrees. If 3X + 2X = 180, then 5X = 180 so X=36 degrees.
The perimeter of a triangle is the sum of the lengths of the three sides.If the three expressions in the question are in fact the lengths of thethree sides, then the perimeter is their sum.(7x + 9w) + (2x + 8y) + (2y + 5w) = 9x + 10y + 14w