GPE = mgh (mass x gravity x height). You can use 9.8 for gravity.
Height= GPE/gravitational constant(mass)
true Jupiter has a larger mass than earthType your answer here...
False on two counts. A rectangular shape is 2-dimensional and so can have no mass. If it is rectangular but has length, width and height then it is a cuboid object. Then, multiplying the length width and height will give the volume, not the mass.
No you could not.
I think, it lies in 1/4 of height measured from the base(in the centre of the square, of course) I did the calculation using integral
The gravitational potential energy of the boulder is given by the formula: GPE = mgh, where m is the mass of the boulder (2500 kg), g is the acceleration due to gravity (9.81 m/s^2), and h is the height above the ground (200 m). Plugging in these values, we get GPE = 2500 kg * 9.81 m/s^2 * 200 m = 4,905,000 J. The boulder's gravitational potential energy is 4,905,000 Joules.
According to Eculator's calculator for velocity of a falling object, the speed of the boulder won't be dependent on its mass and will be given by:v = (2gh)1/2So, the calculated answer putting h = 200 m would be: 62.609903369994115 m/sec
The kinetic energy of the boulder when it is 1000m above the ground is zero because at that height, the boulder is not in motion. The kinetic energy of an object is given by the formula KE = 0.5 * m * v^2, where m is the mass of the object and v is its velocity.
No.Mass is always the same, unless broken apart from one another.
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To find the mass of the boulder, you would need to divide the force (in newtons) by the acceleration due to gravity, which is approximately 9.81 m/s^2. Therefore, the mass of a 980 newton boulder would be about 100 kg.
The formula for potential energy in an object at a height h above the ground is PE mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height above the ground.
Sure, if either of the following conditions is true: -- The smaller mass started dropping before the larger mass did. As long as (MsmallVsmall) is equal or greater than (MbigVbig), the smaller mass has equal or more momentum than the larger one has. But of course, the momentum of the larger mass catches up as its speed grows. -- The smaller mass and the larger mass were dropped at exactly the same time, but on different planets. Then, if the smaller one was dropped in a place where gravitation is greater, and the greater mass was dropped in a place where gravitation is less, it's quite possible for the smaller mass to have more momentum than the larger mass has, at least for a while. If the acceleration of gravity on the larger planet is at least (larger mass x acceleration of gravity on the smaller planet/smaller mass) or more, then the smaller mass has more momentum than the larger mass has forever, or as long as they're both freely falling.
Height and mass
a boulder
Yes, a boulder rolling down a hill has mass and velocity. Therefore, it has momentum because p = mv (momentum = mass x velocity).
The work done in moving a body of mass m to a height h above the ground is given by the equation: work = mgh, where m is the mass of the body, g is the acceleration due to gravity, and h is the height.