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What is the sum of the measures of the interior angles of the regular polygon if each exterior measures 120?
Hint: in a regular polygon interior plus exterior = 180o, always.
What is the sum of the measures of the exterior angles of a polygon?
If you multiply 360 by the number of angles in the polygon and then subtract the sum of all the interior angles you will end up with the sum of all the exterior angles of the polygon.
What polygon does the sum of the measures of interior angles equal the sum of the measures of the exterior angles?
A 4 sided quadrilateral has interior angles that add up to 360 degrees and its exterior angles add up to 360 degrees
What is the sum of the measures of the interior angles of a regular polygon if each exterior angle measures 72?
540 degrees
Interior and exterior angles of a 30 sided polygon?
The total of the interior angles equal 5040, and each angle measures 168 degrees The total of the exterior angles equal 360, and each angle measures 12 degrees
What is the sum of the measures of the interior angles of the regular polygon if each exterior measures 120?
Hint: in a regular polygon interior plus exterior = 180o, always.
What is the sum of the measures of the exterior angles of a polygon?
If you multiply 360 by the number of angles in the polygon and then subtract the sum of all the interior angles you will end up with the sum of all the exterior angles of the polygon.
What is the sum of the measures of the interior angles of a regular of a regular polygon if each exterior angle measures 120?
If exterior angles are 120 then interior angles must be 60 so you have an equilateral triangle
What polygon does the sum of the measures of interior angles equal the sum of the measures of the exterior angles?
A 4 sided quadrilateral has interior angles that add up to 360 degrees and its exterior angles add up to 360 degrees
What is the sum of the measures of the interior angles of a regular polygon if each exterior angle measures 90?
360
One exterior angle of a regular polygon measures 40 What is the sum of the polygon's interior angle measures?
The sum of a regular polygon's interior angles is always equal to (n-2) * 180, where n is the number of sides in the polygon. Given that one exterior angle measures 40 degrees, we can find the interior angle by subtracting 40 from 180 degrees (since the exterior and interior angles are supplementary) to get 140 degrees. So, the sum of the interior angles of the regular polygon is 140 * n.
What is the sum of the measures of the interior angles of a regular polygon if each exterior angle measures 72?
540 degrees
Interior and exterior angles of a 30 sided polygon?
The total of the interior angles equal 5040, and each angle measures 168 degrees The total of the exterior angles equal 360, and each angle measures 12 degrees
What is the sum of the measures of the interior angles of a regular polygon if each exerior angle measures 72 degrees?
There are 5 interior angles and each one measures 108 degrees (180-72). Since the sum of exterior angles of any polygon is 360⁰, then that polygon would have 5 angles (360/72). So the sum of interior angle measures is 540⁰.
What is the sum of the measures of the interior angles of a polygon if each exterior angle measures 120 degrees?
The 3 interior angles of this equilateral triangle will add up to 180 degrees
What is the sum of the measures of the interior angles of a regular polygon if each exterior angle measures 90 degrees?
360 degees
What is the sum of the measures of the interior angles of a regular polygon if each exterior angle measures 120?
180
