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In the right triangle abc angle c is the right angle line ac is 3 and line ab is 5 so if point d is on hypotenuse ab that is to 1 what is the area of dbc?
The triangle is a right angled triangle with sides measuring 3 (and 4) and the hypotenuse of length 5.
Note - The length of the third side bc = 4, can be calculated using Pythagoras Theorem.
If d is 1 unit of length along the hypotenuse and a perpendicular line is drawn from bc to d (meeting bc at e) then the triangle bde is similar to triangle bac.
Then ca/ba = 3/5 = ed/bd = ed/1. Thus ed = 3/5 units in length.
The area of a triangle = ½ x base x vertical height.
The area of triangle dbc = ½ x bc x ed = ½ x 4 x 3/5 = 1.2 sq units.
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