Designate the length by L. From the Pythagorean theorem, the length of the diagonal of a square, which divides the square into two right triangles, each with sides L (and the diagonal as hypotenuse to each right triangle), is square root of 2L2 = 4 (from the problem statement). Squaring both sides separately yields 2L2 = 16 or L = square root of 8 = 2 (square root of 2).
L
Let us consider a line l such that it is the perpendicular bisector of line segment AB and the line intersects at point C.Let us take any point on line l(say, D). Join A to D and B to D.Now we have two triangles ACD and BCD.Now, in triangles ACD & BCD, we haveCD = CD (Common side)�ACD = �BCD (Right angle)AC = BC (Since l bisects AB)According to Side-Angle-Side criteria: Both triangles are congruent.Since both triangles are congruent, therefore AD = BD.So, l is the set of all points equidistant from A & B.Hence proved.
pyramid
The altitude/height of an equilateral triangle can be calculated by taking the perpendicular bisector of any side. This line will bisect its opposite angle forming two congruent right angled triangles. The side length of the original equilateral triangle is the hypotenuse and the short leg of right angled triangle is half the hypotenuse. By Pythagoras' Theorem : 42 = 22 + L2.........where L is the length of the altitude. L2 = 42 - 22 = 16 - 4 = 12 L = √12 = 2√3 = 3.464 (3dp)
Designate the length by L. From the Pythagorean theorem, the length of the diagonal of a square, which divides the square into two right triangles, each with sides L (and the diagonal as hypotenuse to each right triangle), is square root of 2L2 = 4 (from the problem statement). Squaring both sides separately yields 2L2 = 16 or L = square root of 8 = 2 (square root of 2).
if it is a perfect L, it is a right angle. if it is more then perfect, its an obtuse if it is less than perfect, /_, it is acute
h e l l o
L
Angle -gieco53
Adele is pretty awsome
Let us consider a line l such that it is the perpendicular bisector of line segment AB and the line intersects at point C.Let us take any point on line l(say, D). Join A to D and B to D.Now we have two triangles ACD and BCD.Now, in triangles ACD & BCD, we haveCD = CD (Common side)�ACD = �BCD (Right angle)AC = BC (Since l bisects AB)According to Side-Angle-Side criteria: Both triangles are congruent.Since both triangles are congruent, therefore AD = BD.So, l is the set of all points equidistant from A & B.Hence proved.
pyramid
The L stands for Lateral and the A stands for Area. Put together, it's Lateral Area!
The altitude/height of an equilateral triangle can be calculated by taking the perpendicular bisector of any side. This line will bisect its opposite angle forming two congruent right angled triangles. The side length of the original equilateral triangle is the hypotenuse and the short leg of right angled triangle is half the hypotenuse. By Pythagoras' Theorem : 42 = 22 + L2.........where L is the length of the altitude. L2 = 42 - 22 = 16 - 4 = 12 L = √12 = 2√3 = 3.464 (3dp)
For a rectangular pyramid (which is not a square bottom) you can not use the standard formula of Surface Area = B + 1/2 * P * s, because there is more than one slant height.A rectangular pyramid is made up of 1 rectangular baseand 4 triangles going up from the base to the top of the pyramid. The surface area is the area of all five parts added togetherThe first bit is a rectangle so you can find the area of it by multiplying its length times its width.Now we have four triangles, two of them will have a base which is the length of the pyramid and two will have a base which is the width of the pyramid.The area of a triangle is (1/2*bh), where b is the base (either length of width of the rectangle) and h is the slant height (distance from the base to the top of the pyramid).The triangles with base = length and the triangles with base = height will have different slant heights. There will be two triangles of each type so the area of all four triangles will be 2(1/2*ls1) + 2(1/2*ws2) = l*s1 + w*s2If you have been given both slant heights you have enough information to answer the question at this stage,You will have SA = l*w + l*s1 + w*s2(where l is length, w is width, s1 is the slant length of the triangles with base l, s2 is the slant length of the triangles with base w)If you do not have the slant lengths you will have to use the Pythagorean Theorem to find them, this will tell you the slant length of the triangle with base l, will be the square root of (w/2)2 + h2 where h is the height of the pyramid (distance from bottom to top through middle of pyramid) similarly the slant length of the triangle with base w will be the square root of (l/2)2 + h2
yes, you can draw a quadrilateral with on right angle because all sides don't have to be equal for a regular one _ /Right Angle l l l l l/ --------------------------------------------------------------------------- A quadrilateral is a polygon with four sides, so yes. You can use only one right angles, if the polygon has four sides.