No. The sum of the lengths of any two sides must be greater than the length of the third.
by getting the longest length and poking yourself
1cm=0.01m (1cm)²=(0.01m)² 1cm²=(0.01)²m²=0.0001m² 81.9cm²=0.00819m²
6CM3
1inch is bigger than 1cm as there is 2.5cm's in 1inch. Hope this helps :)
actual size in inches = 6.1 inches x 8.89 inches24mm * 1cm/10mm * 2.54 inches/1cm= 60.96/10= 6.1 inches35mm * 1cm/10mm * 2.54 inches/1cm= 88.9/10= 8.89 inches
no it is not. you need to have a teacher help you with your problems. i have problems too. i have a toe in my nose. but back on subject it is not possible because you nedd chicken suop. not just any... Campbells! have a nice day sir...mam... idk?
taking a triangle as an example; place the compass at any 1 vertex and then take a radius eg-1cm, from the vertex,cut 1cm on either sides of the adj sides of the triangle den,draw an arc joining both d points marked by d compass, now join the pt of intersectn wtn the vertx.
No 1+3=4, which is less than 5
0.000...1cm length on two sides. 19.999...9cm length on the other two.
8 cubic centimetre
The metric unit that measures the length of your finger is typically in centimeters (cm).
by getting the longest length and poking yourself
If you are talking about 9cm, 9cm and 1cm then yes it can form a triangle because this would be an isosceles triangle. The two longer sides add up to longer than the short side so it can be a triangle.
If an object weights 50mm its will be 5 centimetres
Assuming no fractional dimensions, least possible area would be a rectangle measuring 1cm x 9cm. Area increases to a maximum of 25 sq cm when shape is square, ie 5cm x 5cm.
134 cubes left.
The question cannot be answered because volume is a measure in 3-dimensional space and requires three measures. There are only two given in the question.