Isosceles trapezoid ABCD has an area of 276 If AD = 13 inches and DE = 12 inches, find AB.
28.00
It is 5 inches.
7x
The average(mean) of the two bases. (8+12)/2=10
1 yd = 3 ft 1 foot = 12 in 1 foot squared = 12 inches x 12 inches 1 foot squared = 144 squared inches 1 yard squared = 3 feet by 3 feet 1 yard squard = 9 squared feet 1 yard squared = 9 squared feet x 144 squared inches 1 yard squared =1296 squared inches 5 yards squared = 1296 squared inches x 5 5 yards squared = 6480 inches squared
28.00
It is 5 inches.
Nine feet squared equates to 1,296 inches squared. ** feet squared x 144 = inches squared
576
7x
6.5 feet squared.
630 cm squared equals 97.65 inches square.
The average(mean) of the two bases. (8+12)/2=10
yes- for example imagine a rectangle. One lenght is 5in and the other is 10im. The area is 5inx10im= 50in squared
'A' squared plus 'B' squared equals 'C' squared. If 'A' and 'B' are the legs of the right angle comprising the sides of the box, 30 inches squared (900) plus 30 inches squared (900) equals 1800. The square root of 1800 is 42.426408711929.
(6 sq ft) x (144 sq in per sq ft) = 864 square inches
Three square feet equals 432 square inches.