A square with a side length of 6 inches has an area of 36 square inches.
11 inches
One side of a square is 10 inches long. How many one square inch tiles are needed to cover its area?
To find the area of a square, you multiply the length of one side by itself. In this case, if the sides are 6 inches long, the area would be 6 inches * 6 inches = 36 square inches.
Since the square root of 81 is 9, each side of the square would be 9 centimetres in length.
The area would be 81 square inches.
Each side is 20 inches. 20 x 20 = 400 square inches.
11 inches
The area of square is : 6.25
Its area is one hundred forty four square inches.
The area of square is : 1600.0
Area of a square = side2 Square A area = a2 Square B area = (4a)2 (4a)(4a) = 16a2 The area of square B is sixteen times the area of square A. Proof: Side of square A = 2 inches Side of square B = (4*2) = 8 inches Area of A = 22 = 4 square inches Area of B = 82 = 64 square inches 64 / 4 = 16
All sides of a square are equal. Area of a square = length * width Area = 4 inches * 4 inches Area = 16 inches2
36cm squared Answer: If a square is nine INCHES on a side, its area will be measured in square inches. The formula for area is side times side, 9"X9"= 81 square inches. If the square is made up of nine one inch squares, that would be 3"x3"= 9 square inches.
20 inches.
One side of a square is 10 inches long. How many one square inch tiles are needed to cover its area?
6561
a square buddy. what type of knucklehead asks this type of question?