The question, as it appears, cannot be answered without the following assumptions - none of which have any justification for making them.
RST and JKL are triangles. The triangles are similar and in correspondence follows their naming. If that is true then the perimeter of JKL is 48 cm.
It is angle RST.
Perimeter = 12+12+7+7 = 38 inches
It is: 7+8+12 = 27 cm
12 the base times the height
4 inches x 3 sides = 12 inches for the perimeter.
find the perimeter of a square that has 12 m side
Perimeter of 12" by 8" = 12+8+12+8 = 40 inches.
Perimeter = 12 + 12 + 8 + 8 = 40.
It is angle RST.
To find the perimeter of any polygon just add the length of everyside. In this case you have 4 sides with a length of 12 in. so 12 + 12 + 12 + 12 = perimeter. or to simplify 4 * 12 = perimeter.
by multiplying 15 and 12 twice then add up your answer and that's the perimeter
The angle opposite side RT = 12 will have the smallest measure
Perimeter = 12+12+7+7 = 38 inches
The perimeter of this is 5yd+3yd+4yd+=12 yds
All you do is add the sides up for the perimeter. 12 + 10 + 9 = 31
to get the perimeter you take 12 x 2 and 22 x 2 get those numbers then add them and you have your perimeter
It is: 7+8+12 = 27 cm