As you were copying the question, did you notice the drawing alongside it ?
Well, see, that sketch is actually part of the question; anybody who wants to
try and answer it needs to see that drawing.
It will be 1/3 of the circle's circumference
It is: 72-lenghth of major arc = length of minor arc
Minor arc/Circumference = 150/360 Minor arc = 31.4*150/360 = 13.0833...
An arc length of 120 degrees is 1/3 of the circumference of a circle
I'm assuming that "c" is short for "circumference". The length of an arc is (circumference)*(360/angle). So the length of an arc in a circle with circumference length of 18.84 is 6782.4/angle, where the angle is measured in degrees.
It will be 1/3 of the circle's circumference
It is: 72-lenghth of major arc = length of minor arc
Minor arc/Circumference = 150/360 Minor arc = 31.4*150/360 = 13.0833...
circumference = 2*pi*7 = 43.98229715 arc = (120/360)*43.98229715 = 14.66076572 or 14.661 units rounded to 3 dp
An arc length of 120 degrees is 1/3 of the circumference of a circle
A central angle of 120 is one third of the circle, so the arc length of 28.61 is one third of the circumference. 28.61 X 3 = 85.83
I'm assuming that "c" is short for "circumference". The length of an arc is (circumference)*(360/angle). So the length of an arc in a circle with circumference length of 18.84 is 6782.4/angle, where the angle is measured in degrees.
A+ 13.03^.^
Arc length = pi*r*theta/180 = 17.76 units of length.
It is 5 cm.
312 cm
To find the arc length of a minor arc, you can use the formula: ( \text{Arc Length} = \frac{\theta}{360} \times 2\pi r ), where ( \theta ) is the angle in degrees and ( r ) is the radius. For a 120-degree arc with an 8-unit radius, the arc length is ( \frac{120}{360} \times 2\pi \times 8 = \frac{1}{3} \times 16\pi = \frac{16\pi}{3} ). Thus, the arc length is approximately 16.76 units.