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First of all we work out the length of a sides ab, bc, CD, & ad.

We know that ab = bc = CD = ad

also ae = ac/2

If a to e = 2 then ac = 4

so

ab2 + bc2 = ac2

2ab2 = 16

ab2 = 8

ab = 2.8284271247461900976033774484194

so the perimeter = ab * 4 = 11.31

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12y ago
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Q: The diagonals of square abcd intersect at e if ae equals 2 find to perimeter of abcd?
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