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10 and -10 -10 + 20 = 10 (2 x -10) + (12 x 10) = 100 To solve, where X is the smaller number, Y is the larger: X + 20 = Y 2X + 12Y = 100 Substitute for Y: 2X + 12(X + 20) = 100 2X + 12X + 240 = 100 14X = -140 X = -10 OR: X = Y - 20 2X + 12Y = 100 Substitute for X 2(Y - 20) + 12Y = 100 2Y - 40 + 12Y = 100 14Y = 140 Y = 10

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Q: The larger of two numbers is 20 more than the smaller when 2 times the smaller is added to 12 times the larger the result is 100 what two numbers are you thinking of?
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