Suppose the angle is x. Then its complement is 90-x
x - 50 = 90 - x or 2x = 140 so that x =70.
(90 - 78)/2 ie 6o
40 degres
74
Suppose the angle is x degrees. It is 26 deg more than its complement so the complement is x - 26 degrees. Since the two angles are complementary, their sum is 90 degrees. That is x + x - 26 = 90 or 2x - 26 = 90 so that 2x = 116 and so x = 58 degrees.
The angle is 50 and its compliment is 40.
It is: 90-36 = 54 degrees
25
A complement of an acute angle must be an acute angle. An acute angle is an angle whose measure is more than 0 degrees but less than 90 degrees. For example, even if the angle was the minimum 1 degree, the complement is still 89 degrees, which is still acute. Therefore, any combination of a complement of an acute angle MUST be acute.
The complement of any angle, given that the angle is less than 90 degrees, is 90 minus the angle measure. In other words, it is, "What degree measure, when added to the original angle, creates 90 degrees?"
The complement of an angle which measures D degrees, where D must be less than 90, is 90 - D.
(90 - 78)/2 ie 6o
ans: 50 degree. its complement is 90-50=40 degree
36 and 54 degrees.
Suppose the angle is x. Then its complement is 90-x. So x = (90-x) + 28 = 118 - x So 2x = 118 and x = 59 (with complement 31).
40 degres
The information given in the question is tautological. By definition, the measure of the supplement of any angle will be 90 degrees more than its complement. So the answer isany angle, x degrees where 0
74