51 degrees
The interior angles of a quadrilateral always add up to 360 degrees. Therefore, 68+51+116=235 360-235=125 degrees.
39
The supplement of a 51° angle is 129° since the sum of the angles that form the supplementary angles is 180°.
Complimentary angles add to 90 degrees. So, x + y = 90. Also, we know the difference is 12 degrees. So, x - y = 12. (Note that it really doesn't matter which angle corresponds to x and y. The way it is set up here is x is the larger angle.) Now solve the system: x + y = 90 x - y = 12 2x = 102 x = 51 y = 90 - 51 = 39 So the two angles are 51 degrees and 39 degrees.
It is 51 degrees.
51 degees
An angle greater than 51 degrees is possibly an right angle or can be a obtuse angle.
51 degrees
The interior angles of a quadrilateral always add up to 360 degrees. Therefore, 68+51+116=235 360-235=125 degrees.
I will assume that this is referring to a triangle. The angles of a triangle add up to 180 degrees. Let the missing angle = a then a + 22 degrees + 51 degrees = 180 degrees a = 107 degrees
39
90-39 = 51 degrees
Since the sum of the angles of a triangle is 180 degrees, we have:(11x - 4) + (4x - 11) + (51 - 3x) = 18011x + 4x - 3x - 4 -11 + 51 = 18012x + 36 = 180 (subtract 36 from both sides)12x = 144 (divide by 12 to both sides)x = 12The measure of angle A = 11x - 4 = 11(12) - 4 = 132 - 4 = 128 degrees, which is the largest angle of the triangle. Therefore, the longest side a is opposite to the angle A.The measure of angle B = 4x - 11 = 4(12) - 11 = 48 - 11 = 37 degrees. The side b is opposite to the angle B.The measure of angle C = 51 - 3x = 51 - 3(12) = 51 - 36 = 15 degrees, which is the smallest angle of the triangle. Therefore, the shortest side c is opposite to the angle C.Thus, we can list the sides of the triangle from the shortest to the longest as c, b, and a.
The degrees or the angle of slope of the sides of the pyramid is on the pyramids at Giza is about 51 degrees
The complementary angle of 51o is 39o; the supplementary angle of 51o is 129o.
180 -51 -63 = 66 degrees