The question is not very coherent. However if the sides either side of BC are able to meet at a point, then the angle between BC and the adjacent sides must be less than 90 degrees. Hence the shape can only be a triangle and since it's regular the angle must be 60 degrees. So if n is 3, the angle (60) is 20n.
A triangle has 3 sides and so the length of bc will depend on its perimeter.
If ab and ac are each as long as bc then the triangle is, in fact, equilateral, not just isosceles. Therefore, each side is 20/3 cm = 6.66... recurring cm.
Perpendicular would be at a right angle. If your sides are abcd, then ab, bc, cd, and da are perpendicular pairs.
Six. If the sides are labelled a, b, c and d then the congruent pairs are: ab, ac, ad, bc, bd and cd
The question is not very coherent. However if the sides either side of BC are able to meet at a point, then the angle between BC and the adjacent sides must be less than 90 degrees. Hence the shape can only be a triangle and since it's regular the angle must be 60 degrees. So if n is 3, the angle (60) is 20n.
For two sides to be parallel they must not meet at a point (vertex). A triangle has only 3 sides. Let the vertices of a triangle be ABC; then the 3 sides of the triangle are AB, AC and BC. The sides AB and AC meet at vertex A, so they cannot be parallel. The sides AB and BC meet at vertex B, so they cannot be parallel. So Side AB is not parallel to AC (meets at vertex A) and not parallel to BC (meets at vertex B). The only possibility left is that side BC is parallel to side AC. But the sides BC and AC meet at vertex C so they cannot be parallel. Thus none of the sides of a triangle can be parallel.
rays BE and BC
the next cup on bc bow contest is the tar cup and its out now!
800 bc greece
A triangle has 3 sides and so the length of bc will depend on its perimeter.
Roman rule in Britannia lasted from 43 BC to around 410 BC. Roman rule extended to England and Wales.
I think it has none ,bc a square doesn't
First, draw the equilateral triangle ABC, and its altitude AI. Extend the sides AB and AC in such way that the extended parts to be equal in length with the length of these sides. Extend also the altitude AI in such way that the extended part to be twice in length as the altitude length. Label their end points , started from the point C, respectively with D, K, and G. From points D, K, and G, draw the parallel lines to BG, BC, and CD. Label their intersections respectively with E and F. A hexagon is formed, the hexagon BCDEFG, where its sides are equal in length with the length sides of the equilateral triangle ABC.
Cleopatra met Julius Caesar in 47 BC.
Under Darius, the Persian Empire extended to the city of Taxila in Central Asia. He was emperor from 521 to 486 BC.
The Shang Dynasty (1600 BC -1046 BC) is said to have amasused, though they also extended their rule over China and rival power Chinese powers.