There is no such polyhedron. The numbers given in the question do not satisfy the Euler characteristic for simply connected polyhedra.
Alternatively, the fact that it has eight faces means that is should be an octahedron. However, among the 257 topologically distinct convex octahedra, the maximum number of vertices is 12 and the maximum number of edges is 18. Both these numbers are well below what you require!
Faces=9 Vertices: 9 Edges=16
It has 8 vertices, 12 edges and 6 faces.
A pyramid with an n-sided base will have n + 1 vertices, n + 1 faces, and 2n edges. 16 edges, 9 vertices
A decahedron is a polyhedron with 10 faces. There are several versions of a decahedron, but none of these are regular. By definition, they all have 10 faces. There is the octagonal prism - with 24 edges and 16 vertices, the square anti-prism, with 16 edges and 8 vertices, the square cupola, with 20 edges and 12 vertices, the pentagonal bi-pyramid, with 15 edges and 7 vertices and the augmented pentagonal prism, with 19 edges and 11 vertices. See, for example, http://en.wikipedia.org/wiki/Decahedron
An octagonal pyramid.
Faces: 10 Vertices: 16 Edges: 24
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Faces: 10 Vertices: 16 Edges: 24
It has 6 faces, 16 edges, and 8 vertices.
Faces = 9 Vertices = 9 Edges = 16
16 vertices 24 edges 17 faces
There is 16 vertices,10 faces,and 24 edges.
Faces=9 Vertices: 9 Edges=16
An octagonal prism has: 10 faces 16 vertices and 24 edges :)
Oh, dude, it's like a math riddle! So, if a polyhedron has 10 more edges than vertices, we can use Euler's formula: Faces + Vertices - Edges = 2. Since we know the relationship between edges and vertices, we can substitute that in and solve for faces. So, it would have 22 faces. Math can be fun... sometimes.
An octagonal prism has: 10 faces 16 vertices and 24 edges :)
Octagonal pyramid: 9 faces 16 edges 9 vertices.